NIMCET 2027 Time and Work Previous Year Question Paper and Solution with PDF

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NIMCET 2027 Previous Year Questions (PYQs)

NIMCET 2027 Time And Work PYQ

Qus : 1 NIMCET 2027 PYQ

Two pipes A and B can fill the cistern in 37.5 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2020 PYQ

Solution

Qus : 2 NIMCET 2027 PYQ

A can do a work in 10 days, B can do the same work in 20 days. After working for 4 days B left the job & C started working at the place of B, the remaining work was done by both A & C in 2 days. In how many days C alone can do the work?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2023 PYQ

Solution

Work and Time – Find Days for C

A's 1 day work: $ \frac{1}{10} $
B's 1 day work: $ \frac{1}{20} $

Step 1: A and B work for 4 days:
Work done = $ 4 \times \left( \frac{1}{10} + \frac{1}{20} \right) = 4 \times \frac{3}{20} = \frac{3}{5} $

Remaining work: $ 1 - \frac{3}{5} = \frac{2}{5} $

Step 2: A and C do remaining work in 2 days:
$ 2 \times \left( \frac{1}{10} + \frac{1}{C} \right) = \frac{2}{5} $

Dividing both sides by 2:
$ \frac{1}{10} + \frac{1}{C} = \frac{1}{5} $

$ \frac{1}{C} = \frac{1}{5} - \frac{1}{10} = \frac{1}{10} $
$ \Rightarrow C = 10 $

✅ Final Answer: 10 days

Qus : 3 NIMCET 2027 PYQ

Computer A takes 3 minutes per input.

Computer B takes 5 minutes per input.

Let C take x minutes per input.

Together A + B + C process:

14 inputs per hour = $\dfrac{14}{60}$ inputs per minute.

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2009 PYQ

Solution

Rates: A: $\dfrac{1}{3}$ per minute B: $\dfrac{1}{5}$ per minute C: $\dfrac{1}{x}$ per minute Total rate: $\dfrac{1}{3} + \dfrac{1}{5} + \dfrac{1}{x} = \dfrac{14}{60} = \dfrac{7}{30}$ Compute: $\dfrac{8}{15} + \dfrac{1}{x} = \dfrac{7}{30}$ $\dfrac{1}{x} = \dfrac{7}{30} - \dfrac{16}{30} = -\dfrac{9}{30}$ Rate cannot be negative → No such x exists. So:

Qus : 4 NIMCET 2027 PYQ

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is/are sufficient to answer the given question. Read both statements and

Give the answer (U) if the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.
Give the answer (V) if the data in statement I| alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.
Give the answer (W) if the data either in Statement I or in Statement II alone are sufficient to the answer of the question.
Give the answer (X) if the data in both statements I and II together are not sufficient to answer the question.
Give the answer (Y) if the data in both statements I and II together are are necessary to answer the question.

How much time will the leak take to empty the full cistern?

The cistern is normally filled in 9 hours.
It takes one hour more than the usual time to fill the cistern because of a leak in the bottom.

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2019 PYQ

Solution

Qus : 5 NIMCET 2027 PYQ

Give the answer (U) if the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.
Give the answer (V) if the data in statement I| alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.
Give the answer (W) if the data either in Statement I or in Statement II alone are sufficient to the answer of the question.
Give the answer (X) if the data in both statements I and II together are not sufficient to answer the question.
Give the answer (Y) if the data in both statements I and II together are are necessary to answer the question.

How will long it take to empty the tank if both the inlet pipe P1 and the outlet pipe P2 are opened simultaneously?

P1 can fill the tank in 16 minutes.
P2 can empty the full tank in 8 minutes.

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2019 PYQ

Solution

Qus : 6 NIMCET 2027 PYQ

How long would it take you to count 1 billion orally if you could count 200 every minute and were given a day off every four years? Assume that you start counting on 1 January 2001.

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2009 PYQ

Solution

Numbers counted per minute = 200

Time needed for 1,000,000,000 numbers:

Minutes required = 1,000,000,000 / 200

= 5,000,000 minutes

Convert minutes:

5,000,000 minutes = 5,000,000 / 60 = 83,333.33 hours

= 3,472.22 days

Now include days off:

From 1 Jan 2001 to finish time → during this period, leap years add 1 day off every 4 years.

Total days ≈ 3472 + 1 leap day = 3473 days

Convert 3473 days to years:

3473 days = 9 years + remaining days

9 years = 3287 days

Remaining = 3473 – 3287 = 186 days

Now convert the decimal part of hours:

0.22×24 ≈ 5.20 hours

0.20×60 ≈ 20 minutes

Final answer = 9 years, 187 days, 5 hours, 20 minutes

Qus : 7 NIMCET 2027 PYQ

A man walks down an escalator.

If he walks down 26 steps, he takes 30 seconds.

If he walks down 34 steps, he takes 18 seconds.

Time is measured from when the top step begins to descend until he steps off at the bottom.

What is the height of the stairway in steps?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2009 PYQ

Solution

Let escalator speed = x steps/sec

Walking speed = y steps/sec

26 = (x + y) × 30

34 = (x + y) × 18

Solving gives x = 0.4, y = 0.47

Total steps = escalator speed × total time

= (x × time when he stands still)

Height = 52 steps

Qus : 8 NIMCET 2027 PYQ

Directions for questions 83–85:

Mrs. Thomes received a large order for stitching school uniforms from Mayflower school and Little flower school. She has two cutters who will cut the fabric, five tailors who will do the stitching and two assistants to stitch the buttons and button holes. Each of these nine persons will work for exactly 10 hours a day. Each of the Mayflower uniforms requires 20 min for cutting the fabric, one hour for stitching, and 15 min for stitching buttons and button holes, whereas the Little flower uniform requires 30 min, 1 hour and 30 min respectively for these activities.

What is the number of Little flower uniforms that Mrs. Thomes can complete in a day?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2011 PYQ

Solution

Little flower uniform requires:

• Cutting = 30 min

• Stitching = 60 min

• Buttons = 30 min

Available daily working time:

• 2 cutters → 2 × 600 min = 1200 min

• 5 tailors → 5 × 600 min = 3000 min

• 2 assistants → 2 × 600 min = 1200 min

Calculate max number by each stage:

Cutting capacity = 1200 / 30 = 40

Stitching capacity = 3000 / 60 = 50

Button work capacity = 1200 / 30 = 40

Minimum of these = 40 uniforms

Qus : 9 NIMCET 2027 PYQ

On a particular day, Mrs. Thomes decided to complete 20 Little flower uniforms. How many Mayflower uniforms can she complete on that day?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2011 PYQ

Solution

Little flower uniform uses per piece:

Cutting 30 min → 20 uniforms = 600 min

Stitching 60 min → 20 uniforms = 1200 min

Buttons 30 min → 20 uniforms = 600 min

Remaining capacity:

Cutters: 1200 – 600 = 600 min

Tailors: 3000 – 1200 = 1800 min

Assistants: 1200 – 600 = 600 min

Mayflower uniform time:

Cutting = 20 min → capacity = 600 / 20 = 30

Stitching = 60 min → capacity = 1800 / 60 = 30

Buttons = 15 min → capacity = 600 / 15 = 40

Minimum = 30 uniforms

Qus : 10 NIMCET 2027 PYQ

If she hires one more assistant, what is the maximum number of Mayflower uniforms that she can complete in a day?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2011 PYQ

Solution

Mayflower uniform requires:

Cutting = 20 min

Stitching = 60 min

Buttons = 15 min

Daily capacity:

Cutters: 1200 min → 1200 / 20 = 60

Tailors: 3000 min → 3000 / 60 = 50

Assistants: previously 2 (1200 min), now 3 assistants → 3 × 600 = 1800 min

Buttons capacity = 1800 / 15 = 120

Minimum of 60, 50, 120 = 50 uniforms

Qus : 11 NIMCET 2027 PYQ

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2022 PYQ

Solution

Let the required number of bottles be x.

More machines, More bottles (Direct Proportion)

More minutes, More bottles (Direct Proportion)

$\begin{matrix}{\begin{matrix}{Machines} & {6\colon10}\end{matrix}} \\ {\begin{matrix}{Time} & {\, \, \, \, \, \, \, \, \, \, 1\colon4}\end{matrix}}\end{matrix}\Bigr{\}}: : 270:x$

∴$6×1×x=10×4×270$

⇒$x= \frac{(10×4×270)}{6}$

⇒$x=1800$

Qus : 12 NIMCET 2027 PYQ

Two pipes A and B can fill a cistern in 37.5 and 45 min, respectively. Both pipes are opened. The cistern will be filled in just half an hour, if pipe B is turned off after

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2018 PYQ

Solution

Qus : 13 NIMCET 2027 PYQ

A caterpillar crawls up a pole of 75 inches high, starting from the ground. Each day, it crawls up 5 inches and each night it slides down 4 inches. When will it reach the top of the pole?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2018 PYQ

Solution

Qus : 14 NIMCET 2027 PYQ

A child can do a piece of work 15 hours slower than a woman. The child works for 18 hours on the job and then the woman takes charge for 6 hours. In this way, 3/5 of the work is completed. To complete the job now, how much time does the woman take?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2010 PYQ

Solution

Let the woman finish the whole work in W hours. Then the child finishes it in W + 15 hours. Work done: Child’s 18 hours work = 18 / (W + 15) Woman’s 6 hours work = 6 / W Total = 3/5 So, 18/(W+15) + 6/W = 3/5 Solve: Multiply by 5W(W+15): 5W·18 + 5(W+15)·6 = 3W(W+15) 90W + 30W + 450 = 3W² + 45W 120W + 450 = 3W² + 45W 3W² - 75W - 450 = 0 Divide by 3: W² - 25W - 150 = 0 Solve quadratic: W = [25 ± √(625 + 600)] / 2 W = [25 ± √1225] / 2 W = (25 ± 35) / 2 Positive solution → W = (25 + 35)/2 = 30 hours

Qus : 15 NIMCET 2027 PYQ

Two men and three boys can do a piece of work in ten days; while three men and two boys can do the same work in eight days. In how many days can two men and one boy do the work?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2018 PYQ

Solution

Qus : 16 NIMCET 2027 PYQ

If 1 man or 2 women can finish a job in 20 days, how may days will 3 men and women take to finish the same job?

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NIMCET 2027 Previous Year PYQ NIMCET 2027 NIMCET 2025 PYQ

Solution

$1$ man or $2$ women can finish the work in $20$ days.

Work by $1$ man in $1$ day $= \dfrac{1}{20}$
Work by $1$ woman in $1$ day $= \dfrac{1}{40}$

For $3$ men and $1$ woman:
Total work per day $= 3 \times \dfrac{1}{20} + 1 \times \dfrac{1}{40}$
$= \dfrac{6}{40} + \dfrac{1}{40} = \dfrac{7}{40}$

Time to finish the job $= \dfrac{1}{(7/40)} = \dfrac{40}{7}$ days
$\approx 5.71$ days

✅ Final Answer: $ \dfrac{40}{7} $ days

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NIMCET 2027 Time And Work PYQ

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Work and Time – Find Days for C

✅ Final Answer: 10 days

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