WB JECA MCA Computer Previous Year Question Paper and Solution with PDF

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WB JECA MCA
Previous Year Questions

WB JECA MCA
Previous Year Questions
WB JECA MCA

if(x > 10)

printf("Greater");

else if(x = 10)

printf("Equal");

else

printf("Smaller");

return 0;

}

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Solution

Assignment x=10 makes condition true → prints "Equal".

Qus : 19 WB JECA MCA PYQ

In FP-Growth Algorithm, FP means __________

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Solution

In FP-Growth, FP stands for Frequent Pattern, used in association rule mining.

Qus : 20 WB JECA MCA PYQ

What will be output of the following code snippet?

#include int main()

{

int i;

for (i=1;i<=5;i++)

{

if(i == i)

continue;

printf("%d ", i);

}

return 0;

}

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Solution

Condition i==i always true → continue always → nothing printed.

Qus : 21 WB JECA MCA PYQ

In software engineering, what is the full form for PERT chart?

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Solution

Program Evaluation and Review Technique

Qus : 22 WB JECA MCA PYQ

Which of the following statements about arrays in C is correct?

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Solution

Array name gives base address; indexing starts from 0.

Qus : 23 WB JECA MCA PYQ

In software engineering, the testing performed by development team is known as ______.

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Solution

Alpha testing is performed internally by the development team before releasing the software for beta testing.

Qus : 24 WB JECA MCA PYQ

Read the following statements about functions in C and choose the correct option:

(i) A function in C can return only one value directly.

(ii) Function names can be the same as variable names in the same scope.

(iii) A function must always take at least one argument.

(iv) Recursion is allowed in C functions.

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Solution

(i) true, (ii) false, (iii) false, (iv) true.

Qus : 25 WB JECA MCA PYQ

In software engineering, a prototyping model can be used when __________.

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Solution

Technical solutions are unclear to the development team

Qus : 26 WB JECA MCA PYQ

What happens when a recursive function in C lacks a proper base condition?

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Solution

No base condition → infinite recursion → stack overflow.

Qus : 27 WB JECA MCA PYQ

60.In classical waterfall model, which phase comes before the design phase?

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Solution

Requirements analysis and specification

Qus : 28 WB JECA MCA PYQ

What will be the output of the following C code?

#include int main()

{

int a = 10;

int *p = &a;

TCP provides a full-duplex service — meaning data can flow simultaneously in both directions.

Qus : 40 WB JECA MCA PYQ

What will be the output of the following program?

#include int main()

{

char str1[20] = "Hello ";

char str2[20] = "Hello";

strcpy(str2, str1);

if (strcmp(str1, str2) == 0)

printf("Equal ");

else

#include int main()

{

int x;

x = 4<3?100:3==3?2?50:75;

printf("%d", x);

return 0;

}

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Solution

4<3 false → evaluate next → 3==3 true → 2?50:75 → 50.

Qus : 120 WB JECA MCA PYQ

Five elements P, Q, R, S, T are pushed onto a stack starting from P. The stack is then popped 4 times, and each popped element is inserted into a queue. Two elements are then deleted from the queue and pushed back onto the stack. Finally, one element is popped from the stack. What will be the popped element?

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Solution

Final popped element becomes Q after operations.

Qus : 121 WB JECA MCA PYQ

What is the output of the following code snippet?

#include <stdio.h>
main() {
int x = 65, *p = &x;
void *q = p;
char *r = q;
printf("%c", *r);
}

(A) $A$

(B) $Z$

(D) None of the above

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Solution

Step 1: Initialization

$x = 65$
In ASCII, $65 \equiv A$

Step 2: Pointer flow
$p = \&x \;\; \rightarrow$ pointer to integer
$q = p \;\; \rightarrow$ void pointer
$r = q \;\; \rightarrow$ typecast to char pointer

Step 3: Dereferencing
Since r is char*, it reads 1 byte.
The value stored = $65$

Step 4: Printing
printf("%c", *r); prints character with ASCII $65$.
Hence, the output is:

$\; \boxed{A} \;$

Correct Answer: (A)

Qus : 122 WB JECA MCA PYQ

Consider the following operations on a singly linked list initially containing the elements: 10 → 20 → 30 → 40

(i) Insert 15 after 10

(ii) Delete node containing 30

(iii) Insert 25 at end

(iv) Delete first node.

What will be the final sequence?

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Solution

Final list: 20 → 15 → 25 → 40.

Qus : 123 WB JECA MCA PYQ

In pipelining, the CPU instruction is divided into stages (Fetch, Decode, Execute, etc.).
To maximize throughput, each stage must complete within 1 clock cycle.
This ensures that new instructions can enter the pipeline without delay.

Correct Answer: (A) 1

Qus : 126 WB JECA MCA PYQ

Find the output from the following C++ code snippet:

class A

{

public: void show()

{

cout<<"Class A ";

}

};

class B: public A

{

public: void show()

{

A::show();

cout<<"Class B";

}

};

int main()

{

B obj;

obj.show();

}

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Solution

Calls A::show then prints Class B.

Qus : 127 WB JECA MCA PYQ

Relational calculus is a

(A) Procedural language

(B) Non-procedural language

(D) High-level language

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Solution

Relational Algebra is procedural (it specifies how to obtain the result).
Relational Calculus is non-procedural (it specifies what to obtain, not how).

Therefore, Relational Calculus is a Non-procedural language.

Correct Answer: (B) Non-procedural language

Qus : 128 WB JECA MCA PYQ

What will be the output of this program?

#include using namespace std;

class Test

{

public: static int x;

Test()

{

x++;

}

void display()

{

cout<

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Solution

x=5 → t1→6, t2→7.

Qus : 129 WB JECA MCA PYQ

How many parameters does a default constructor require ?

(A) 1

(B) 2

(D) 3

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Solution

A default constructor in C++ is a constructor that takes no arguments.
It is invoked automatically when an object is created without passing parameters.

Hence, it requires 0 parameters.

Correct Answer: (C) 0

Qus : 130 WB JECA MCA PYQ

What is the output of the following C++ code?

#include using namespace std;

class Base

{

public: virtual void show()

{

cout<<"Base";

}

};

class Derived: public Base

{

public: void show()

override{ cout<<"Derived"; }

};

int main()

{

Base* ptr;

Derived d;

ptr=&d;

ptr->show();

return 0;

}

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Solution

Virtual function → Derived called.

Qus : 131 WB JECA MCA PYQ

An artificially intelligent car decreases its speed based on its distance from the car in front of it. Which method is used?

(A) Naive Bayes
(B) Decision Tree
(C) Linear Regression
(D) Logistic Regression

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Solution

The car’s speed is a continuous variable that depends on the distance from the car ahead.
To model this relation, we need a method for predicting a continuous outcome.

Linear Regression is used because it maps distance (input) to speed (output).

Correct Answer: (C) Linear Regression

Qus : 132 WB JECA MCA PYQ

Which of the following are true about cyclomatic complexity?

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Solution

Cyclomatic complexity counts independent paths; higher value = more complex.

Qus : 133 WB JECA MCA PYQ

The keyword friend does not appear in

(A) the class allowing access to another class.

(B) the class desiring access to another class.

(D) the public section of a class.

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Solution

The friend keyword is used inside a class definition to allow another class or function to access its private/protected members.
It appears in the class granting access (not the one desiring access).
It can be declared in either public or private section of that class.

Hence, it does not appear in the class desiring access.

Correct Answer: (B) the class desiring access to another class

Qus : 134 WB JECA MCA PYQ

A testing phase executes 180 test cases out of 200 planned, with 162 passes and 18 failures. Which are true?

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Solution

Execution=180/200=90%, Pass=162/180=90%, Req=85%.

Qus : 135 WB JECA MCA PYQ

What is the maximum number of level-2 DFD possible if the number of processes in level-1 DFD is n ?

(A) $\frac{n}{2}$

(B) 2

(D) n

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Solution

In a Data Flow Diagram (DFD), each process in level-1 can be decomposed further into its own level-2 diagram.

Therefore, if there are n processes at level-1, then maximum possible level-2 DFDs = n.

Correct Answer: (D) $n$

Qus : 136 WB JECA MCA PYQ

In the context of Software Development Life Cycle (SDLC), which of the following statements is correct?

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Solution

V-model aligns testing with each development phase.

Qus : 137 WB JECA MCA PYQ

The small extremely fast RAM's are termed as ______

(A) Heap

(B) Accumulators

(D) Cache

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Solution

Heap → Memory area for dynamic allocation.
Accumulator → Register in CPU for intermediate results.
Stack → Memory area used for function calls and local variables.
Cache → Small, high-speed RAM located close to the CPU, used to store frequently accessed data.

Hence, the correct answer is Cache.

Qus : 216 WB JECA MCA PYQ

What is the output of the following C program?

#include <stdio.h>
void main(){
  int a = -7;
  float b;
  b = a++;
  printf("%d, %f ", a, ++b);
}

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Solution

Explanation: The statement b = a++; assigns the current value of a (−7) to b and then increments a to −6. Later, ++b increments b from −7 to −6 before printing. $$ a = -6,\quad b = -6.000000 $$

Qus : 217 WB JECA MCA PYQ

What is the output?

#include <stdio.h>
void main(){
  int i = -1;
  printf("sizeof(i) = %d", sizeof(i));
}

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Solution

Explanation: The operator sizeof gives the size of the type in bytes, not the value. On most 32-bit and 64-bit systems, sizeof(int) is 4. $$ \text{Output: } \texttt{sizeof(i) = 4} $$

Qus : 218 WB JECA MCA PYQ

What is the output?

#include <stdio.h>
void main(){
  int x = -1, y = 1, z = 0;
  if(x && y++ && z)
    ++x, y++, --z;
  printf("%d, %d, %d", x++, y++, z++);
}

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Solution

Explanation: In the condition x && y++ && z, since z = 0, the logical AND short-circuits and the body of the if is not executed. However, y++ is evaluated before the short-circuit, so y becomes 2. Values before printing: $$ x = -1,\ y = 2,\ z = 0 $$ So the program prints: $$ (-1,\ 2,\ 0) $$

Qus : 219 WB JECA MCA PYQ

What is the output?

#include <stdio.h>
enum colors{RED, BROWN, ORANGE};
void main(){
  printf("%ld..%f..%d", RED, BROWN, ORANGE);
}

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Solution

Explanation: The format specifiers do not match the data types (%f is used for int). This causes undefined behavior. The program may compile, but the output is not reliable. Correct choice: None of these.

Qus : 220 WB JECA MCA PYQ

What is the output?

#include <stdio.h>
void main(){
  char M = 'M';
  printf("%d, %c", M, M);
}

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Solution

Explanation: The character 'M' has an ASCII value of 77. So printing with %d shows 77, and %c shows M. $$ \text{Output: } 77,\ M $$

Qus : 221 WB JECA MCA PYQ

What is the output?

#include <stdio.h>
void main(){
  int i = -9;
  printf("%d %d %d", i++, ++i, ++i);
}

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Solution

Ek hi expression me variable i par multiple modifications → C standard me undefined behavior.
Isliye koi fixed output/compile error guarantee nahi. Sahi option: None of these.

Qus : 222 WB JECA MCA PYQ

What is the output?

#include <stdio.h>
void main(){
  int **ptr;
  int temp = 65;
  ptr[0] = &temp;
  printf("%d", ptr[0][0]);
}

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Solution

Explanation: The pointer ptr is uninitialized, so it does not point to valid memory. When the code tries to access ptr[0], it attempts to dereference an invalid location. This leads to undefined behavior, and in most cases results in a segmentation fault.

Qus : 223 WB JECA MCA PYQ

What is the output?

#include <stdio.h>
#include <stdlib.h>
void main(){
  int *ptr;
  ptr = (int*) calloc(3, sizeof(int));
  ptr[2] = 30;
  printf("%d", *ptr);
  free(ptr);
}

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Explanation: fork() creates a new process (child) as a copy of the calling process.

Qus : 238 WB JECA MCA PYQ

24. In file management, FAT means ______________.

(A) Feature Access Table (B) File Access Table (C) Fault Allocation Table (D) File Allocation Table

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Solution

Explanation: FAT stands for File Allocation Table, a file system layout used to map files to disk clusters.

Qus : 239 WB JECA MCA PYQ

25.What is the output of the following program ? include <iostream> using namespace std; int addition (int a, int b) { return a+b; } double addition (double a, double b) { return a+b; } int main () { cout<< addition (35,20) << “;”; cout<< addition (34.1,12.7); return 0; }

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Solution

The given program defines two overloaded functions `addition`:

1. `int addition(int a, int b)` → returns integer sum

2. `double addition(double a, double b)` → returns double sum

In `main()`:

- `addition(35,20)` calls the integer version → 35 + 20 = 55

- `addition(34.1,12.7)` calls the double version → 34.1 + 12.7 = 46.8

Therefore, the output is:

55;46.8

Qus : 240 WB JECA MCA PYQ

26.What is the output of the following program ? #include <iostream> using namespace std; template <class C1, class C2> bool is_equal (C1 var1, C2 var2) { return (var1 = = var2); } int main () { if (is_equal(10,10.0)) cout<< “Equal”; else cout<< “Not equal”; return 0; }

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Solution

The function `is_equal` is a template that compares two variables of possibly different types.

In `main()`, we call `is_equal(10, 10.0)`.

- `10` is an integer (int).

- `10.0` is a double.

C++ allows implicit type conversion during comparison.

So, `10 == 10.0` evaluates to `true`.

Therefore, the condition in the `if` statement is true, and the output will be:

Equal

Qus : 241 WB JECA MCA PYQ

26.What is the output of the following program ?

#include <iostream>

using namespace std;

int main()

{

int var = 0;

while (var < 10)

{

cout << var << " ";

var++;

}

cout << var;

return 0;

}

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Solution

Output:

0 1 2 3 4 5 6 7 8 9 10

Explanation:

The variable var starts at 0.
The while (var < 10) loop prints 0 1 2 3 4 5 6 7 8 9 with spaces.
When var reaches 10, the loop stops.
After the loop, cout << var; prints 10.

Final output:
```
0 1 2 3 4 5 6 7 8 9 10
```

Qus : 242 WB JECA MCA PYQ

What is the output of the following program ?

#include <iostream>

using namespace std;

struct demo

{

int var;

};

int main()

{

demo str;

demo *ptr;

str.var = 100;

ptr = &str;

cout << ptr->var;

return 0;

}

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Solution

Output:

100

Explanation:

str.var = 100; assigns 100 to the structure variable.

ptr = &str; makes the pointer point to str.

ptr->var accesses the member var of structure str via pointer.

Hence it prints 100.

Qus : 243 WB JECA MCA PYQ

29.What is the output of the following program ?

#include <iostream>

using namespace std;

int main ()

{

int c1 = 10;

int c2 = 20;

{

int c1;

c1 = 50;

c2 = 50;

cout << "c1= " << c1 << ", c2=" << c2;

}

cout << ", c1= " << c1 << ", c2=" << c2;

return 0;

}

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Solution

Output:
c1= 50, c2=50, c1= 10, c2=50
Explanation:

Outer c1 = 10, c2 = 20.

Inside the inner block, a new local c1 is declared (shadowing outer c1).

Inner c1 = 50, and c2 (outer one) is updated to 50.

First cout prints → c1= 50, c2=50.

After the block ends, inner c1 is destroyed. Outer c1 remains 10, while outer c2 is 50.

Second cout prints → , c1= 10, c2=50.

? Final output: c1= 50, c2=50, c1= 10, c2=50.

Qus : 244 WB JECA MCA PYQ

30.What is the output of the following program ?

#include <iostream>

using namespace std;

class Demo {

public:

static int count;

Demo() { count++; }

};

int Demo::count = 0;

int main() {

Demo var1;

Demo var2[5];

cout << var1.count;

return 0;

}

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Solution

Explanation:
- int Demo::count = 0; initializes the static variable count to 0.
- Demo var1; → constructor is called once → count = 1.
- Demo var2[5]; → constructor is called 5 times (for each element in the array) → count = 6.
- Since count is static, it is shared among all objects.
- Finally, cout << var1.count; prints 6.
? Correct answer: (A) 6 ✅

Qus : 245 WB JECA MCA PYQ

31.What is the output of the following program ?

#include <iostream>

using namespace std;

void print();

int main()

{

int var = 0;

var = print();

cout << var;

return 0;

}

void print()

{

cout << "Hi";

}

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Solution

Explanation:
- print() is declared as void print().
- In main(), the statement var = print(); tries to assign the return value of print() to an int variable.
- But since print() has no return value (void), this causes a compile-time error.
Hence, the program does not compile.

Qus : 246 WB JECA MCA PYQ

32.What is the output of the following program ?

#include <iostream>

using namespace std;

int main()

{

int var = 2;

{

cout << var;

} while (var--);

return 0;

}

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Solution

Explanation:
- Initially var = 2.
- First iteration: prints 2, then var-- makes var = 1.
- Second iteration: prints 1, then var-- makes var = 0.
- Third iteration: prints 0, then var-- makes var = -1. Condition fails and loop exits.
So output is:

Qus : 247 WB JECA MCA PYQ

33.In shell script, which command is used to create a new directory ?

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Solution

mkdir is the command to create a new directory in Unix/Linux.

Qus : 248 WB JECA MCA PYQ

34.In shell script, which command is used to copy a file?

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Solution

cp is used to copy files or directories in Unix/Linux.

Qus : 249 WB JECA MCA PYQ

35.In shell script, which command is used to delete a file?

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Solution

rm is the command to remove/delete files in Unix/Linux.

Qus : 250 WB JECA MCA PYQ

36.In Unix/Linux platform, which command is used to find out the difference between two files?

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Solution

diff compares two files line by line and shows differences.

Qus : 251 WB JECA MCA PYQ

37.In Unix/Linux platform, which command is used to create a symbolic link?

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Solution

ln -s is used to create symbolic (soft) links in Linux.

Qus : 252 WB JECA MCA PYQ

38.In Unix/Linux platform, which command is used to view the inode number of a file?

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Solution

ls -i displays the inode number of each file.

Qus : 253 WB JECA MCA PYQ

39.In Unix/Linux platform, which command is used to specify the access mode for files?

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Solution

chmod is used to change file permissions (read/write/execute).

Qus : 254 WB JECA MCA PYQ

40.In Unix/Linux platform, ______ command is used to show current running processes.

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Solution

ps shows the list of currently running processes.

Qus : 255 WB JECA MCA PYQ

In singly linked list, the time complexity for insertion at a particular node is:

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Solution

Insertion after a given node in a linked list takes constant time O(1) (if pointer to that node is already available).

Qus : 256 WB JECA MCA PYQ

In stack data structure, __________ operation is not permitted.

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WB JECA MCA Previous Year PYQ WB JECA MCA JECA MCA 2023 PYQ

Solution

Enqueue is a queue operation, not allowed in stack.

Qus : 257 WB JECA MCA PYQ

In tree data structure, the in-degree of root node is always __________.

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WB JECA MCA Previous Year PYQ WB JECA MCA JECA MCA 2023 PYQ

Solution

The root node has no incoming edges, so its in-degree is always 0.

Qus : 258 WB JECA MCA PYQ

In binary tree data structure, using depth-first approach, preorder traversal means _______.

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WB JECA MCA Previous Year PYQ WB JECA MCA JECA MCA 2023 PYQ

Solution

Preorder traversal visits root first, then left subtree, then right subtree.

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WB JECA MCA Previous Year Questions (PYQs)

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In pipelining, the CPU instruction is divided into stages (Fetch, Decode, Execute, etc.).
To maximize throughput, each stage must complete within 1 clock cycle.
This ensures that new instructions can enter the pipeline without delay.