1
A-II, B-III, C-I, D-IV 2
A-III, B-IV, C-II, D-I 3
A-IV, B-III, C-II, D-I 4
A-IV, B-III, C-I, D-II Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution Dog causes Rabies, Mosquito causes Malaria → A-IV
Amnesia affects Memory, Paralysis affects Movement → B-III
Meningitis affects Brain, Cirrhosis affects Liver → C-II
Influenza is caused by Virus, Typhoid is caused by Bacteria → D-I
Correct matching: A-IV, B-III, C-II, D-I
Qus : 3
CUET PYQ
1
A. If $(12P)_3 = (123)_p$, then value of $P$ is infeasible.
B. The simplified sum of product form of the Boolean expression is
$(P+\bar Q+\bar R)(P+\bar Q+R)(P+Q+\bar R)$
C. The minimum number of D flip-flops needed to design a mod-$(258)$ counter is $8$.
Choose the correct answer from the options given below:
1
A only
2
A and B only 3
A and C only
4
C only Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution A: Base-3 number $(12P)_3$ implies $P<3$, but $(123)_p$ implies base $p>3$ ⇒ infeasible → True
B: Given expression is not in simplified SOP form → False
C: For mod-$258$, $2^8=256<258$, so minimum flip-flops required = 9 → False
Qus : 4
CUET PYQ
1
A RAM chip has a capacity of $1024$ words of $8$ bits each $(1k \times 8)$.
The number of $2 \times 4$ decoders with enable line needed to construct a $16k \times 16$ RAM from $1k \times 8$ RAM is ______.
1
5 2
4 3
7 4
6 Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution To go from $1k$ to $16k$:
$16k/1k=16 \Rightarrow 4$ additional address lines.
A $2\times4$ decoder selects $4$ blocks using $2$ lines.
For $16$ blocks, $4$ such decoders are required, and with enable control one more decoder is needed.
Total decoders $=5$
Qus : 5
CUET PYQ
1
If $\oplus$ and $\odot$ denote exclusive OR and exclusive NOR operations respectively, then which one of the following is not correct?
1
$P\oplus Q=P\odot Q$ 2
$\bar P\oplus Q=P\odot Q$ 3
$\bar P\oplus\bar Q=P\oplus Q$ 4
$(P\oplus\bar P)+Q=(P\odot\bar P)\odot Q$ Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution XOR and XNOR are complements of each other.
Statement (1) claims them equal, which is false.
Qus : 6
CUET PYQ
3
Arrange the following steps in the correct order to understand the functioning of a 3 to 8 line decoder.
(A). The encoder enable input is set to 1.
(B). The decoder activates one of its 8 output lines based on the input code.
(C). The input binary code is applied to the decoder.
(D). The decoder converts the 3-bit binary input into 8 possible outputs.
Choose the correct answer from the options given below:
1
(A), (B), (C), (D) 2
(A), (D), (C), (B) 3
(A), (C), (D), (B) 4
(A), (B), (D), (C) Go to Discussion
CUET Previous Year PYQ
CUET CUET 2025 PYQ
Solution
To understand the functioning of a 3-to-8 line decoder:
• (A) Enable input is set to 1.
• (C) Apply the 3-bit binary input.
• (D) Decoder converts the 3-bit input into 8 possible outputs.
• (B) Finally, one of the 8 output lines is activated based on the input code.
✅ Therefore, the correct sequence is:
\[
(A), (C), (D), (B)
\]
Qus : 8
CUET PYQ
2
What should be the minimum hamming distance dmin to guarantee correction of upto p errors in a given block code.
1. 2p
2. 2p+1
3. 2p-1
4. $2^{p-2}$
1
1 2
2 3
3 4
4 Go to Discussion
CUET Previous Year PYQ
CUET CUET 2025 PYQ
Solution
We know the relationship between minimum Hamming distance
\(d_{\min}\) and error correction capability \(p\):
\[
d_{\min} \;\geq\; 2p + 1
\]
This ensures the code can correct up to \(p\) errors .
✅ Correct answer:
\[
\boxed{2p+1}
\]
Qus : 9
CUET PYQ
2
Match List-I with List-II
List-1 List-II JK Flip Flop inputs Next State (A). 0 0 (I). Toggle (B). 0 1 (II). Set (C). 1 0 (III). Reset (D). 1 1 (IV). No Change
Choose the
correct answer from the options given below:
1. (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
2. (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
3. (A) - (IV), (B) - (III), (C) - (I), (D) - (II)
4. (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
1
1 2
2 3
3 4
4 Go to Discussion
CUET Previous Year PYQ
CUET CUET 2025 PYQ
Solution
JK Flip-Flop Truth Table (Inputs → Next State)
(A) 0 0 → (IV) No Change
(B) 0 1 → (III) Reset
(C) 1 0 → (II) Set
(D) 1 1 → (I) Toggle
✅ Correct Answer: Option 2
Qus : 11
CUET PYQ
3
Minimum number of 2:1 Multiplexers required to design a 16:1 Multiplexer is?
1
12 2
14 3
15 4
16 Go to Discussion
CUET Previous Year PYQ
CUET CUET 2025 PYQ
Solution
To implement an \(n:1\) multiplexer using only \(2:1\) multiplexers, the minimum number required is:
\[
\text{Number of 2:1 MUX} = n - 1
\]
For \(n = 16\):
\[
16 - 1 = 15
\]
✅ Therefore, the minimum number of \(2:1\) multiplexers required to design a \(16:1\) multiplexer is:
\[
\boxed{15}
\]
Qus : 12
CUET PYQ
3
A 2’s-complement adder–subtracter can add or subtract binary numbers.
Sign-magnitude numbers represent ______ decimal numbers, and 2’s complements stand for ______ decimal numbers.
1
hexa, sign 2
sign, hexa 3
positive, negative 4
negative, positive Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution In sign-magnitude representation, a separate sign bit is used, mainly representing positive numbers explicitly.
2’s-complement representation is primarily used to represent negative numbers in binary arithmetic.
Qus : 13
CUET PYQ
1
Consider the following statements.
(A). Combinational logic circuits do not have memory, while sequential logic circuits have memory elements.
(B). Sequential logic circuits depend only on the current inputs,while combinational logic circuits depend on both
current and past inputs.
(C). Flip-flops and latches are examples of combinational logic circuits.
(D). Multiplexer is an example of combinational logic circuit.
Choose the correct statement/statements from the options given below:
1. (A) and (D) only
2. (A), (B) and (D) only
3. (A), (B), (C) and (D)
4. (B), (C) and (D) only
1
1 2
2 3
3 4
4 Go to Discussion
CUET Previous Year PYQ
CUET CUET 2025 PYQ
Solution
Solution
(A). ✅ Correct. Combinational logic circuits do not have memory. Sequential circuits include memory elements.
(B). ❌ Incorrect. Sequential circuits depend on both current and past inputs (via memory) , while combinational circuits depend only on current inputs.
(C). ❌ Incorrect. Flip-flops and latches are examples of sequential circuits , not combinational circuits.
(D). ✅ Correct. Multiplexer (MUX) is a combinational logic circuit.
Correct Statements: (A) and (D)
Answer: Option 1
Qus : 16
CUET PYQ
1
A logic circuit, that can odd two 1-bit numbers and produce output for sum and carry but cannot handle carry, input, is called ____________.
1
Half adder
2
Full adder
3
Multiplexer
4
Encoder
Go to Discussion
CUET Previous Year PYQ
CUET CUET 2024 PYQ
Solution
A circuit that adds two 1-bit numbers and produces outputs for Sum and Carry but does not handle carry input is called a Half Adder .
A B Sum (A⊕B) Carry (A·B)
0 0 0 0
0 1 1 0
1 0 1 0
1 1 0 1
Boolean Expressions:
Sum = \( A \oplus B \)
Carry = \( A \cdot B \)
Final Answer: The circuit is a Half Adder .
Qus : 17
CUET PYQ
3
Column A
Column B
A. AND
I. Output 1 only if both inputs are 1
B. OR
II. Output 1 if any input is 1
C. NAND
III. Output 0 only if both inputs are 1
D. NOR
IV. Output 1 only if both inputs are 0
Options
(a) (A)-IV, (B)-III, (C)-II, (D)-I
(b) (A)-I, (B)-III, (C)-IV, (D)-II
(c) (A)-I, (B)-II, (C)-III, (D)-IV
(d) (A)-II, (B)-I, (C)-IV, (D)-III
1
(a) 2
(b) 3
(c) 4
(d) Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution
Qus : 19
CUET PYQ
2
Column A
Column B
A. Counter register
I. Read by host to get input
B. Status register
II. Written by host to sent output
C. Data in register
III. Contain bit that can be read by host
D. Data out register
IV. Can be written by host to start command
Options
(a) (A)-I, (B)-II, (C)-III, (D)-IV
(b) (A)-IV, (B)-III, (C)-I, (D)-II
(c) (A)-III, (B)-IV, (C)-II, (D)-I
(d) (A)-I, (B)-II, (C)-IV, (D)-III
1
(a) 2
(b) 3
(c) 4
(d) Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution
Qus : 20
CUET PYQ
4
A target thread periodically checks whether it should terminate, allowing it an opportunity to terminate itself in an orderly fashion.
(a) synchronous cancellation
(b) asynchronous cancellation
(c) default cancellation
(d) deferred cancellation
1
(a) 2
(b) 3
(c) 4
(d) Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution
Qus : 21
CUET PYQ
1
Match the following:
Column A Column B Decoder I. Select input and output of many Multiplexer II. convert binary input into 2n output Encoder III. convert 2n input into binary output Demultiplexer IV. route one input to several output
Options:
(a) Decoder – II, Multiplexer – I, Encoder – III, Demultiplexer – IV (b) Decoder – III, Multiplexer – I, Encoder – II, Demultiplexer – IV (c) Decoder – II, Multiplexer – III, Encoder – I, Demultiplexer – IV (d) Decoder – III, Multiplexer – IV, Encoder – II, Demultiplexer – I
1
(a) 2
(b) 3
(c) 4
(d) Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution
Qus : 22
CUET PYQ
1
Half adder has
(a) two input two output
(b) one input two output
(c) two input one output
(d) one input one output
1
(a) 2
(b) 3
(c) 4
(d) Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution A Half Adder is a combinational circuit used to add two binary bits. Inputs: A, B → 2 inputs Outputs: Sum (S) and Carry (C) → 2 outputs
Sum = A ⊕ B Carry = A · B
Qus : 23
CUET PYQ
1
Which of the following are combinational circuit
A. Half adder
B. SR flip flop
C. Full adder
D. D flip flop
Options:
(a) A, C
(b) B, D
(c) B, C, D
(d) A, B, C, D
1
(a) 2
(b) 3
(c) 4
(d) Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution Half Adder → Combinational circuit Full Adder → Combinational circuit
SR Flip Flop → Sequential circuit D Flip Flop → Sequential circuit
Combinational circuits depend only on present input, while sequential circuits depend on present input and previous state.
Correct Answer: (a) A, C
Qus : 24
CUET PYQ
4
Arrange the following steps of K-map simplification in correct order.
(A) Write minimized SOP / POS expression
(B) Plot truth table outputs (0's and 1's) on K-map
(C) Identify prime implicants and essential prime implicants
(D) Draw groups (loops) of adjacent 1's or 0's that are powers of 2
Options:
(a) A, B, C, D
(b) C, A, B, D
(c) B, C, A, D
(d) B, D, C, A
1
(a) 2
(b) 3
(c) 4
(d) Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution Step 1: Plot truth table outputs on K-map → (B) Step 2: Draw groups (loops) of adjacent 1's or 0's → (D) Step 3: Identify prime implicants and essential prime implicants → (C) Step 4: Write minimized SOP / POS expression → (A)
Correct Order: B → D → C → A
Correct Answer: (d) B, D, C, A
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CUET
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