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CUET Previous Year Questions (PYQs)

CUET Hyperbola PYQ


CUET PYQ
The tangent to the hyperbola $x^2-y^2=3$ are parallel to the straight line $2x+y+8=0$ at the following points:





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Solution

Slope of line $2x+y+8=0$ is $-2$. Slope of tangent to hyperbola is $\dfrac{x}{y}$. Set $\dfrac{x}{y}=-2 \Rightarrow y=-\dfrac{x}{2}$. Substitute in $x^2-y^2=3$ ⇒ $x=\pm2$, $y=\mp1$.

CUET PYQ
The foci of hyperbola coincide with foci of ellipse $ \frac{x^2}{25} + \frac{y^2}{9} = 1 $. So the equation of hyperbola if $e = 2$ is 

(a) $ \frac{x^2}{4} - \frac{y^2}{12} = 1 $ 
(b) $ \frac{x^2}{16} - \frac{y^2}{12} = 1 $ 
(c) $ \frac{x^2}{12} - \frac{y^2}{4} = 1 $ 
(d) $ \frac{x^2}{2} - \frac{y^2}{9} = 1 $





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Solution



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