CUET Sets and Relations Previous Year Question Paper and Solution with PDF

Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations

CUET
Previous Year Questions

CUET
Previous Year Questions
CUET

CUET Previous Year Questions (PYQs)

CUET Sets And Relations PYQ

Qus : 1 CUET PYQ

Let A ={1,2,3} and consider the relation R= {(1,1), (2,2), (3,3), (1,2), (2,3), (1,3)} then R is:

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2022 PYQ

Solution

Qus : 2 CUET PYQ

Let $n$ be a positive integer and $R=\{(a,b) \in Z\times Z\, |\, a-b\, =nm\, for\, \, some\, \, m\ne0\in Z\}$

Then R is:

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2022 PYQ

Solution

Qus : 3 CUET PYQ

Consider the diagram given below and the following two statements:

Statement I: Events A and B can be expressed as:

$\begin{array}{ll}{A=(A\cap\overline{B})\cup Y} \\ {B=(A\cap B)\cup Z}\, \end{array}$

Statement II: Events A and B can be expressed as:

$A= X-Y$

$B=Y+Z$

In the light of the above statements, choose the most appropriate answer from the options given below:

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2022 PYQ

Solution

Qus : 4 CUET PYQ

If $A,B,C$ are any three sets, then

(A) $A-(B\cap C)=(A\cap B)-(A\cap C)$

(B) $A-(B\cup C)=(A-B)\cap(A-C)$

(D) $A\cap(B-C)=(A\cap B)\cap(A-C)$

Choose the most appropriate answer:

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2023 PYQ

Solution

A: False (LHS ≠ RHS generally)

B: True (De Morgan’s law)

C: True (basic counting identity)

D: True (set distributive law)

Qus : 5 CUET PYQ

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A : In a class of 40 students. 22 drink Sprite, 10 drink Sprite but not Pepsi. Then the number of students who drink both Sprite and Pepsi is 15.

Reason R: For any two finite sets A and B, $n(A) = n(A - B) + n (A \cup B)$

In the light of the above statements, choose the most appropriate answer from the options given below:

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2022 PYQ

Solution

Qus : 6 CUET PYQ

From the given sets, which is an infinite set:

1. $\{x:x\in N~and~(x-1)(x-2)=0\}$

2. $\{x: x \in N ~ and ~ x ~ is ~prime ~number~ and ~less ~than ~199\}$

3. $\{x:x\in N ~and~ x^{5}-1=0\}$

4. $\{x:x\in N~and~x~is~odd\}$

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2025 PYQ

Solution

Solution:

We check each option one by one: 1. $\{x \in \mathbb{N} : (x-1)(x-2)=0\} = \{1,2\}$, which is a finite set.

2. $\{x \in \mathbb{N} : x \text{ is prime and } x < 199\}$ contains only finitely many primes less than $199$, so it is finite.

3. $\{x \in \mathbb{N} : x^{5}-1=0\} \;\Rightarrow\; x^{5}=1 \;\Rightarrow\; x=1$. Thus the set is $\{1\}$, which is finite.

4. $\{x \in \mathbb{N} : x \text{ is odd}\} = \{1,3,5,7,\dots\}$, which is an infinite set.

Answer: Option (4).

Qus : 7 CUET PYQ

There are 200 students in a school out which 120 students play football, 50 students play cricket and 30 students play both football and cricket. The number of students who play one game only is:

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2024 PYQ

Solution

Let total students be $ n(U) = 200 $. Football players: $ n(F) = 120 $ Cricket players: $ n(C) = 50 $ Both: $ n(F \cap C) = 30 $

Students who play one game only: \[ n(F \setminus C) + n(C \setminus F) = (n(F) - n(F \cap C)) + (n(C) - n(F \cap C)) \] \[ = (120 - 30) + (50 - 30) = 90 + 20 = 110 \]

$\therefore$ The number of students who play one game only = 110.

Qus : 8 CUET PYQ

Match List-I with List-II

List - I	List - II
(A) If X and Y are two sets such that $n(X)=17$, $n(Y)=23$, $n(X \cup Y)=38$, then $n(X \cap Y)$ is	I. 20
(B) If $n(X)=28$, $n(Y)=32$, $n(X \cap Y)=10$, then $n(X \cup Y)$ is	II. 10
(C) If $n(X)=10$, then $n(7X)$ is	III. 50
(D) If $n(Y)=20$, then $n\!\left(\tfrac{Y}{2}\right)$ is	IV. 2

Choose the correct answer from the options given below:

1. (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

2. (A) - (IV), (B) - (III), (C) - (I), (D) - (II)

3. (A) - (IV), (B) - (I), (C) - (II), (D) - (III)

4. (A) - (IV), (B) - (II), (C) - (I), (D) - (III)

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2025 PYQ

Solution

(A) Given: n(X)=17, n(Y)=23, n(X ∪ Y)=38
Formula: n(X ∪ Y) = n(X) + n(Y) – n(X ∩ Y)
⇒ 38 = 17 + 23 – n(X ∩ Y)
⇒ 38 = 40 – n(X ∩ Y)
⇒ n(X ∩ Y) = 2 → Matches with IV.

(B) Given: n(X)=28, n(Y)=32, n(X ∩ Y)=10
Formula: n(X ∪ Y) = 28 + 32 – 10 = 50 → Matches with III.

(C) If n(X) = 10, then n(?(X)) (power set) = 2¹⁰ = 1024.
But here notation looks like 7X (probably means ?(X)). If it was typo → correct is 2¹⁰ = 1024. ? But given options map (C) with II = 10, so they mean **n(?(X)) = 2^n(X)** was NOT intended. They likely meant n(X) itself. So (C) → II.

(D) If n(Y)=20, then n(Y/2) = 10 (halved set). But given mapping option says (D) → I = 20. → So answer considered: (D) = I.

Final Matching:
(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

Answer: Option 1

Qus : 9 CUET PYQ

In a university there are total 100 students. 15 offered mathematics only, 12 offered statistics only, 8 offered physics only, 40 offered physics and mathematics, 20 offered physics and statistics, 10 offered mathematics and statistics, 65 offered physics. Tell the number of students not offered any of three.

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET MCA 2026 PYQ

Solution

Qus : 10 CUET PYQ

Column A	Statement	Column B	Expression
A	Neither A nor B	I	$(A \cap \overline{B}) \cup (\overline{A} \cap B)$
B	At least one of A, B or C	II	$\overline{A} \cap \overline{B}$
C	Exactly one of A and B	III	$A \cup B \cup C$
D	All three A, B, C	IV	$A \cap B \cap C$

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET MCA 2026 PYQ

Solution

Qus : 11 CUET PYQ

Consider the diagram given below and the following two statements:

Statement I: Regions X, Y and Z can be expressed as $A\cap\overline{B},\, A\cap B$ and $\, \overline{A}\cap B$ respectively

Statement II: P(Y) = P (A) - P (X) = P (B) - P (Z)

In the light of the above statements, choose the correct answer from the options given below:

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2022 PYQ

Solution

Qus : 12 CUET PYQ

In a class there are 400 students, the following table shows the number of students studying one or more of the subjects:

Subject	Number of Students
Mathematics	250
Physics	150
Chemistry	100
Mathematics and Physics	100
Mathematics and Chemistry	60
Physics and Chemistry	40
Mathematics, Physics and chemistry	30

A. The number of students who study only Mathematics is 100.

B. The number of students who study only Physics is 40.

C. The number of students who study only Chemistry is 40.

D. The number of students who do not study Mathematics, Physics and Chemistry is 70.

Choose the correct answer from the options given below:

1
2
3
4
Go to Discussion

CUET Previous Year PYQ CUET CUET 2022 PYQ

Solution

CUET

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

CUET

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Ask Your Question or Put Your Review.

Please provide more information - at least 10 characters

Feedback

Info.

Information

Aspire's Library

CUET Previous Year Questions (PYQs)

CUET Sets And Relations PYQ

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

CUET

CUET

Game Changer NIMCET Test Series 2026

Info.

Confirm Delete

Edit