1
A-II, B-III, C-I, D-IV 2
A-III, B-IV, C-II, D-I 3
A-IV, B-III, C-II, D-I 4
A-IV, B-III, C-I, D-II Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution Dog causes Rabies, Mosquito causes Malaria → A-IV
Amnesia affects Memory, Paralysis affects Movement → B-III
Meningitis affects Brain, Cirrhosis affects Liver → C-II
Influenza is caused by Virus, Typhoid is caused by Bacteria → D-I
Correct matching: A-IV, B-III, C-II, D-I
Qus : 2
CUET PYQ
3
If each of $n$ numbers $x_i = i$ is replaced by $(i+1)x_i$, then the new mean is
1
$\dfrac{(n+1)(n+2)}{n}$ 2
$n+1$ 3
$\dfrac{(n+1)(n+2)}{3}$ 4
$\dfrac{(n+1)(5n+4)}{6}$ Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution Original numbers: $1,2,3,\dots,n$
New values:
$(i+1)i = i^2+i$
Sum of new values:
$\sum i^2 + \sum i = \dfrac{n(n+1)(2n+1)}{6} + \dfrac{n(n+1)}{2}$
$= \dfrac{n(n+1)(2n+1+3)}{6}
= \dfrac{n(n+1)(2n+4)}{6}
= \dfrac{n(n+1)(n+2)}{3}$
New mean:
$\dfrac{(n+1)(n+2)}{3}$
Qus : 3
CUET PYQ
2
The mean deviation from the mean of the A.P.
$a, a+d, a+2d, \ldots, a+2nd$ is
1
$n(n+1)d$ 2
$\dfrac{n(n+1)d}{2n+1}$ 3
$\dfrac{n(n+1)d}{2n}$ 4
$\dfrac{n(n-1)d}{2n+1}$ Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution The A.P. is symmetric with $2n+1$ terms.
Mean deviation from mean for such A.P. is
$\dfrac{n(n+1)d}{2n+1}$.
Qus : 4
CUET PYQ
2
If each observation of raw data whose variance is $\sigma^2$ is multiplied by $h$, then the variance of the new set is
1
$\sigma^2$ 2
$h^2\sigma^2$ 3
$h\sigma^2$ 4
$h+\sigma^2$ Go to Discussion
CUET Previous Year PYQ
CUET CUET 2023 PYQ
Solution If all observations are multiplied by a constant $h$, then variance becomes
$h^2$ times the original variance.
So, new variance $=h^2\sigma^2$.
Qus : 5
CUET PYQ
2
Which of the following are true:
(A) Ogive graph is used to measure the median of the collection of datas.
(B) Two events A and B are such that P(A) = 1/2 and P(B) = 7/12 and P(not A not B) = 1/4 then A and B are
independent events.
(C) Relation for mean, mode and median is given by Mode = 3 Median – 2 Mean.
(D) The number of two–digits even number formed from digits 1,2,3,4,5 is 10
Choose the correct answer from the options given below:
1
(A) and (B) only 2
(A), (C) and (D) Only 3
(C) and (D) Only 4
(B) and (C) Only Go to Discussion
CUET Previous Year PYQ
CUET CUET 2024 PYQ
Solution
Solution:
(A) Ogive is used to determine the Median . ✅ True
(B) Given:
\( P(A) = \tfrac{1}{2}, \; P(B) = \tfrac{7}{12}, \; P(\text{not A and not B}) = \tfrac{1}{4} \)
\( P(A \cup B) = 1 - \tfrac{1}{4} = \tfrac{3}{4} \)
\( P(A \cap B) = P(A) + P(B) - P(A \cup B) \)
\( = \tfrac{1}{2} + \tfrac{7}{12} - \tfrac{3}{4} = \tfrac{1}{3} \)
\( P(A)\cdot P(B) = \tfrac{1}{2} \times \tfrac{7}{12} = \tfrac{7}{24} \neq \tfrac{1}{3} \)
So, A and B are not independent. ❌ False
(C) Empirical relation:
\[
\text{Mode} = 3 \times \text{Median} - 2 \times \text{Mean}
\]
✅ True
(D) Two–digit even numbers from {1,2,3,4,5}:
- Units digit must be even → {2, 4} → 2 choices.
- Tens digit (if repetition allowed) → 5 choices.
\[
\text{Total} = 5 \times 2 = 10
\]
✅ True (with repetition allowed)
✔ Final Answer: (A), (C), and (D) are correct.
Qus : 6
CUET PYQ
4
Mean and variance of 12 observations are $ \frac{9}{2} $ and $4$ respectively. Later it was observed that two observations were considered $9$ and $10$ instead of $7$ and $14$ respectively. If the correct variance is $ \frac{m}{n} $ where $m$ and $n$ are coprime, then $m+n$ is
1
314 2
315 3
316 4
317 Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution
Qus : 7
CUET PYQ
2
Arrange the following in sequence to find variance of individual observation.
(A) compute $ \bar{X} $ of observation $x_1, x_2 \dots x_n$
(B) square the deviation obtain sum $ \sum_{i=1}^{n} (x_i-\bar{X})^2 $
(C) divide the sum $ \sum_{i=1}^{n} (x_i-\bar{X})^2 $ by $n$
(D) take deviation of observation from mean that is $(x_i-\bar{X})$
(a) A, B, C, D
(b) A, D, B, C
(c) A, C, B, D
(d) B, C, D, A
1
(a) 2
(b) 3
(c) 4
(d) Go to Discussion
CUET Previous Year PYQ
CUET CUET MCA 2026 PYQ
Solution
Qus : 9
CUET PYQ
3
The arithmetic mean and standard deviation of series of 20 items were calculated
by a student as 20 cm and 5 cm respectively. But while calculating them an item
15 was misread as 30. Find the correct standard deviation.
1
4.10 2
4.40 3
4.54 4
4.66 Go to Discussion
CUET Previous Year PYQ
CUET CUET 2022 PYQ
Solution
Qus : 10
CUET PYQ
2
Given the marks of 25 students in the class as $\{m_1,m_2,m_3,..m_{25}\}$. Marks lie in the
range of [1-100] and $\overline{m}$ is the mean. Which of the following quantity has the value
zero?
1
$$\sum ^{25}_{i=1}|{{m}}_i-\overline{m}|$$ 2
$$\sum ^{25}_{i=1}\Bigg{(}{{m}}_i-\overline{m}\Bigg{)}$$ 3
$$\sum ^{25}_{i=1}{\Bigg{(}{{m}}_i-\overline{m}\Bigg{)}}^2$$ 4
$$\sum ^{25}_{i=1}\frac{{{m}}_i}{\overline{m}}$$ Go to Discussion
CUET Previous Year PYQ
CUET CUET 2022 PYQ
Solution
[{"qus_id":"11478","year":"2022"},{"qus_id":"11480","year":"2022"},{"qus_id":"11674","year":"2024"},{"qus_id":"11712","year":"2024"},{"qus_id":"16658","year":"2023"},{"qus_id":"16681","year":"2023"},{"qus_id":"16712","year":"2023"},{"qus_id":"16728","year":"2023"},{"qus_id":"17333","year":"2026"},{"qus_id":"17335","year":"2026"}]
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