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CUET UG Mathematics Applied Previous Year Questions (PYQs)

CUET UG Mathematics Applied Ratio And Proportion PYQ


CUET UG Mathematics Applied PYQ
A mixture contains milk and water in the ratio $8:x$.
If 3 litres of water is added in 33 litres of mixture, the ratio of milk and water becomes $2:1$, then value of $x$ is:





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CUET UG Mathematics Applied Previous Year PYQ CUET UG Mathematics Applied CUET UG 2022 Applied Mathematics PYQ

Solution

Initial ratio = $8:x$

Total mixture = 33 litres

Milk = $\frac{8}{8+x}\times 33$
Water = $\frac{x}{8+x}\times 33$

After adding 3 litres water:

Milk remains same

Water becomes

$\frac{x}{8+x}\times 33 + 3$

Given final ratio:

$\frac{\text{Milk}}{\text{Water}}=\frac{2}{1}$

So,

$\frac{\frac{8}{8+x}\times 33}{\frac{x}{8+x}\times 33 + 3}=2$

Multiply by $(8+x)$:

$\frac{264}{33x + 3(8+x)}=2$

$264=2(33x + 24 + 3x)$

$264=2(36x+24)$

$264=72x+48$

$216=72x$

$x=3$

CUET UG Mathematics Applied PYQ
Sitaram, a money lender lent a part of Rs. $200000$ to Shyam at simple interest $6%$ p.a. and the remaining to Sushil at $10%$ p.a. at simple interest.
Sitaram earned an annual interest income of Rs. $18000$.

In what ratio did Sitaram lent the money at $6%$ p.a. and $10%$ p.a. respectively?





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CUET UG Mathematics Applied Previous Year PYQ CUET UG Mathematics Applied CUET UG 2022 Applied Mathematics PYQ

Solution

Let amount lent at $6%$ be $x$.

Then amount lent at $10%$

$=200000-x$

Total interest:

$0.06x+0.10(200000-x)=18000$

$0.06x+20000-0.10x=18000$

$20000-0.04x=18000$

$0.04x=2000$

$x=50000$

So,

Amount at $6%$ = $50000$
Amount at $10%$ = $150000$

Ratio:

$50000:150000$

$=1:3$

CUET UG Mathematics Applied PYQ
Sitaram, a money lender lent a part of Rs. $200000$ to Shyam at simple interest $6%$ p.a. and the remaining to Sushil at $10%$ p.a. at simple interest.
Sitaram earned an annual interest income of Rs. $18000$.

How much money did Shyam borrow?





Go to Discussion

CUET UG Mathematics Applied Previous Year PYQ CUET UG Mathematics Applied CUET UG 2022 Applied Mathematics PYQ

Solution

From previous calculation,

Amount lent at $6%$ = Rs. $50000$

Shyam borrowed at $6%$.

Therefore,

Shyam borrowed Rs. $50000$

CUET UG Mathematics Applied PYQ
Sitaram, a money lender lent a part of Rs. $200000$ to Shyam at simple interest $6%$ p.a. and the remaining to Sushil at $10%$ p.a. at simple interest.
Sitaram earned an annual interest income of Rs. $18000$.

What amount of money is lent at $10%$ p.a. simple interest?





Go to Discussion

CUET UG Mathematics Applied Previous Year PYQ CUET UG Mathematics Applied CUET UG 2022 Applied Mathematics PYQ

Solution

From earlier calculation:

Amount at $6%$ = Rs. $50000$

Total principal = Rs. $200000$

So amount at $10%$

$=200000-50000$

$=150000$

CUET UG Mathematics Applied PYQ
Sitaram, a money lender lent a part of Rs. $200000$ to Shyam at simple interest $6%$ p.a. and the remaining to Sushil at $10%$ p.a. at simple interest.
Sitaram earned an annual interest income of Rs. $18000$.

What is the ratio of the interest paid by Shyam and Sushil respectively?





Go to Discussion

CUET UG Mathematics Applied Previous Year PYQ CUET UG Mathematics Applied CUET UG 2022 Applied Mathematics PYQ

Solution

$50000\times 6% = 3000$

Interest from Sushil:

$150000\times 10% = 15000$

Ratio:

$3000:15000$

$=1:5$


CUET UG Mathematics Applied


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