CUET UG Mathematics Applied Straight line Previous Year Question Paper and Solution with PDF

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CUET UG Mathematics Applied
Previous Year Questions

CUET UG Mathematics Applied
Previous Year Questions
CUET UG Mathematics Applied

CUET UG Mathematics Applied Previous Year Questions (PYQs)

CUET UG Mathematics Applied Straight Line PYQ

Qus : 1 CUET UG Mathematics Applied PYQ

The point of intersection of the lines $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\frac{x-4}{5}=\frac{y-1}{2}=z$ is:

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Go to Discussion

CUET UG Mathematics Applied Previous Year PYQ CUET UG Mathematics Applied CUET UG 2022 Applied Mathematics PYQ

Solution

First line Let parameter $t$ $x=1+2t$ $y=2+3t$ $z=3+4t$ Second line Let parameter $s$ $\frac{x-4}{5}=\frac{y-1}{2}=z=s$ So $x=4+5s$ $y=1+2s$ $z=s$ For intersection $3+4t=s$ Substitute in $x$ $1+2t=4+5(3+4t)$ $1+2t=19+20t$ $-18=18t$ $t=-1$ Then $s=3+4(-1)=-1$ Point $x=1+2(-1)=-1$ $y=2+3(-1)=-1$ $z=3+4(-1)=-1$

Qus : 2 CUET UG Mathematics Applied PYQ

The distance between the point $(3,4,5)$ and the point where the line $\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}$ meets the plane $x+y+z=17$ is:

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Go to Discussion

CUET UG Mathematics Applied Previous Year PYQ CUET UG Mathematics Applied CUET UG 2022 Applied Mathematics PYQ

Solution

Line in parametric form Let parameter $t$ $x=3+t$ $y=4+2t$ $z=5+2t$ Substitute in plane $x+y+z=17$ $(3+t)+(4+2t)+(5+2t)=17$ $12+5t=17$ $t=1$ Point of intersection $x=4$ $y=6$ $z=7$ Distance from $(3,4,5)$ $d=\sqrt{(4-3)^2+(6-4)^2+(7-5)^2}$ $d=\sqrt{1+4+4}$ $d=3$