CUET UG Mathematics Applied Time and Work Previous Year Question Paper and Solution with PDF

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Qus : 1 CUET UG Mathematics Applied PYQ

A pipe can empty $\left(\frac{5}{6}\right)$th part of a cistern in 20 minutes.

The part of cistern which will be empty in 9 minutes is:

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Go to Discussion

Pipe empties $\frac{5}{6}$ part in 20 minutes.

Rate per minute

$=\frac{5}{6} \div 20$

$=\frac{5}{6}\times \frac{1}{20}$

$=\frac{5}{120}$

$=\frac{1}{24}$

So in 1 minute it empties $\frac{1}{24}$ part.

In 9 minutes:

$=\frac{9}{24}$

$=\frac{3}{8}$

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