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MCA NIMCET Previous Year Questions (PYQs)
MCA NIMCET Pair Of Straight Lines PYQ
MCA NIMCET PYQ
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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2024 PYQ
For what values of $\lambda$ does the equation $6x^2 - xy + \lambda y^2 = 0$ represents
two perpendicular lines and two lines inclined at an angle of $\pi/4$.
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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2024 PYQ
Solution
MCA NIMCET PYQ
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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2018 PYQ
The slope of two-lines $6x^2-xy-2y^2=0$ differ by
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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2018 PYQ
Solution
Equation:
\(6x^2 - xy - 2y^2 = 0\)
Compare with: \( ax^2 + 2hxy + by^2 = 0 \)
\(a = 6\)
\(2h = -1 \;\;\Rightarrow\;\; h = -\tfrac{1}{2}\)
\(b = -2\)
Slopes satisfy:
\(bm^2 + 2hm + a = 0\)
\(-2m^2 - m + 6 = 0\)
\(\Rightarrow 2m^2 + m - 6 = 0\)
Solving quadratic:
\(m = \dfrac{-1 \pm \sqrt{49}}{4}\)
\(m = \dfrac{-1 \pm 7}{4}\)
Therefore:
\(m_1 = \tfrac{3}{2}, \quad m_2 = -2\)
Answer:
\( \tfrac{7}{2} \)
MCA NIMCET PYQ
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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2021 PYQ
If θ is acute angle between the pair of lines $x^2-7xy+12y^2=0$, then $\frac{2\cos \theta+3\sin \theta}{4\sin \theta+5\cos \theta}=$
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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2021 PYQ
Solution
MCA NIMCET PYQ
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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2017 PYQ
If x2 + 3xy + 2y2 – x – 4y – 6 = 0 represents a pair of straight lines, their point of intersection is
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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2017 PYQ
Solution
MCA NIMCET
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