AMU MCA C Programming Language Previous Year Question Paper and Solution with PDF

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AMU MCA Previous Year Questions (PYQs)

AMU MCA C Programming Language PYQ

Qus : 1 AMU MCA PYQ

Output of the following C-code

main()

{

printf("Hello");

main();

}

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Recursive call without stopping condition → infinite printing until stack overflow.

Qus : 2 AMU MCA PYQ

Predict the output of the following program:

int main()

{

int arr[5];

// Assume base address of arr is 2000 and size of integer is 32 bit

arr++;

printf("%u", arr);

return 0;

}

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Array name arr represents base address.

Size of int = 32 bit = 4 bytes.

Base address = 2000.

After arr++, pointer moves by one integer = 4 bytes.

New address = 2000 + 4 = 2004.

Qus : 3 AMU MCA PYQ

What is the similarity between a structure, union and enumeration?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2025 PYQ

Solution

struct, union and enum are all user-defined data types in C.

Qus : 4 AMU MCA PYQ

In the following program, how many times “for” loop will be executed?

#include <stdio.h>

int main()

{

int i = 59, j = 10;

for( ; j ; i )

printf("%d", i);

}

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Solution

Loop condition is j, which is non-zero and never changes. Hence the loop runs infinitely.

Qus : 5 AMU MCA PYQ

A pointer is

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Solution

A pointer is defined as a variable that stores the address of another variable.

Qus : 6 AMU MCA PYQ

In the following program, how many times ‘for’ loop will be executed?

#include <stdio.h>

void main()

{

int i = 5;

for (;;)

printf("%d", i);

}

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Solution

The loop condition is for(;;) which has no condition and no termination statement. Hence the loop never stops.

Qus : 7 AMU MCA PYQ

What is the output for the program given below?

#include <stdio.h>

void main()

{

int i = 5;

for (; i < 12; i++);

printf("%d", i);

}

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Solution

The semicolon ; after the for loop makes it an empty loop. The loop increments i until $i = 12$. After the loop ends, printf prints the final value of i.

Qus : 8 AMU MCA PYQ

What is the output of the program given below?

#include <stdio.h>

void main()

{

int i = 500, j = 1000, k = 100;

if (j == 1000 && i > 400)

k = (j == 1000 && i > 499);

printf("k=%d", k);

else

printf("k=%d", k);

}

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Solution

Condition j==1000 && i>400 is true, so if part executes. Inside: (j==1000 && i>499) → both true → value 1 assigned to k. Output is k=1.

Qus : 9 AMU MCA PYQ

What is the output of the following program? #include int main() { int i = 100, j = 300, k; j = i ^ j; i = i ^ j; j = i ^ j; printf("The values of i and j are %d, %d", i, j); return 0; }

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Solution

This is the XOR swap technique. After execution, values of i and j are swapped. So output is 300, 100.

Qus : 10 AMU MCA PYQ

Suppose that in a C program snippet, following statements are used:

i) sizeof(int)

ii) sizeof(int*)

iii) sizeof(int**)
Assuming size of pointer is 4 bytes and size of int is also 4 bytes, pick the most correct answer.

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Solution

Given that size of int = 4 bytes and size of pointer = 4 bytes, sizeof(int) = sizeof(int*) = sizeof(int**) = 4 bytes.

Qus : 11 AMU MCA PYQ

What is the purpose of the following C-function?

void str_function(char *s1)

{

char *p1, *p2, t1;

p1 = s1;

p2 = s1;

while (*p2 != '\0')

p2++;

p2--;

while (p1 < p2)

{

t1 = *p1;

*p1 = *p2;

*p2 = t1;

p1++;

p2--;

}

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Solution

Pointers move from start and end and swap characters until they meet ⇒ string is reversed.

Qus : 12 AMU MCA PYQ

What will be the output of the following code fragment? (Assume that i, j and k are int variables)

i = j = k = 1;

(j + 2) % k / (i + 1);

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Solution

$j=1,\ k=1,\ i=1$ $(j+2)%k = 3%1 = 0$ $0/(i+1)=0/2=0$

Qus : 13 AMU MCA PYQ

What does ‘BREAK’ keyword do in C programming language?

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Solution

break immediately terminates the loop or switch statement.

Qus : 14 AMU MCA PYQ

What will be the output of the following program?

int main()

{

int *p, a = 12;

p = &a;

*p += 1;

printf("12,");

--*p;

printf("%d, %d\n", *p, a);

return 0;

}

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Solution

a=12 → *p+=1 makes a=13. Then --*p makes a=12. Printed output becomes 12,12,12.

Qus : 15 AMU MCA PYQ

Consider the array definition

int num[10] = {3, 3, 3};

Pick the correct answer:

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Solution

Array size is 10, so valid indices are 0 to 9. Hence num[9] is the last element. Uninitialized elements are set to 0.

Qus : 16 AMU MCA PYQ

What is output for the program given below?

#include <stdio.h>

void main()

{

int i = 500, j = 1000, k;

k = (i > 500 && j == 1000);

printf("k = %d", k);

}

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Solution

Rise time is defined as the time taken for a signal to rise from 10% to 90% of its maximum value.

Qus : 17 AMU MCA PYQ

What is output for the program given below?

#include <stdio.h>

void main()

{

int i = 7;

for (; i < 12; i++);

printf("%d", i);

}

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2025 PYQ

Solution

The semicolon after for makes it an empty loop. Loop ends when i = 12, which gets printed.

Qus : 18 AMU MCA PYQ

When the following code is executed, what will be the value of $x$ and $y$?

int x = 1, y = 0;

y = x++;

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Solution

Post-increment assigns old value of $x$ to $y$, then increments $x$. So $y = 1$, $x = 2$.

Qus : 19 AMU MCA PYQ

What is the output for the program given below?

#include <stdio.h>

int main()

{

char i = 2;

switch(i)

{

case '1':

printf("Black\n");

case '2':

printf("White\n");

default:

printf("Red\n");

}

printf("Blue");

return 0;

}

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Solution

Solution:

i = 2 (numeric), but case '2' is character constant with ASCII value 50

No case matches, so default executes → prints Red

After switch, printf("Blue") always runs

Qus : 20 AMU MCA PYQ

What is the output of this C code?

#include <stdio.h>

int main()

{

printf("Hello World! %d \n", x);

return 0;

}

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Solution

Variable x is not declared. Compiler error will occur.

Qus : 21 AMU MCA PYQ

In C++, the declaration

int x; int &p = x;

is same as the declaration

int x, *p; p = &x;

This remark is

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Solution

Reference (&) is not same as pointer (*). Reference cannot be reseated, pointer can.

Qus : 22 AMU MCA PYQ

Assume rand() returns an integer between 0 and 10000 (both inclusive). To simulate throwing a die:

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Solution

Dice values = 1 to 6 rand() % 6 gives 0–5 Add 1 → 1–6

Qus : 23 AMU MCA PYQ

In C++, a variable defined within a block is visible

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Solution

Block scope variable is visible only inside that block from its declaration onward.

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