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Jamia Millia Islamia MCA Previous Year Questions (PYQs)

Jamia Millia Islamia MCA Arithmetic Reasoning PYQ

Jamia Millia Islamia MCA PYQ
If 7 parallel lines are intersected by another set of 7 parallel lines, the number of parallelograms formed is:





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2019 PYQ

Solution

Number of parallelograms formed = ${}^{7}C_{2} \times {}^{7}C_{2}$ = (21 × 21) = 441.
Jamia Millia Islamia MCA PYQ
Jamia Central Library has 510 visitors on Sundays and 240 visitors on other days. The average number of visitors per day in a 30-day month beginning with a Sunday is:





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2019 PYQ

Solution

Number of Sundays in 30 days starting with Sunday = 5 Visitors on Sundays = 5 × 510 = 2550 Visitors on other 25 days = 25 × 240 = 6000 Total visitors = 8550 Average = 8550 ÷ 30 = 285
Jamia Millia Islamia MCA PYQ
Select the ODD number from the given alternatives:





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2019 PYQ

Solution

Check perfect cubes: 2197 = 13³ 3375 = 15³ 2744 = 14³ 4099 ❌ not a perfect cube
Jamia Millia Islamia MCA PYQ
If A stands for ADD, B for SUBTRACT, C for MULTIPLY and D for DIVIDE, then find the value of 2A3B4D2.





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2020 PYQ

Solution

$2A3B4D2 = 2+3-4\div 2 = 5-2 = 3 $
Jamia Millia Islamia MCA PYQ
When two coins are tossed simultaneously, what is the probability of getting at least one tail?





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2020 PYQ

Solution

Total outcomes = HH, HT, TH, TT Favourable outcomes for at least one tail = HT, TH, TT $P(\text{at least one tail}) = \tfrac{3}{4}$
Jamia Millia Islamia MCA PYQ
The total of the ages of Amar, Akbar and Anthony is 80 years. What was the total of their ages three years ago?





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2020 PYQ

Solution

Three years ago, each of the three persons was 3 years younger. So, total age decreased by $3 \times 3 = 9$ years. Hence, $80 - 9 = 71$ years. $\boxed{\text{Answer: (A) 71 years}}$
Jamia Millia Islamia MCA PYQ
If + means ÷, x means –, – means × and ÷ means +, then find the value of $38 + 19 – 16 × 17 ÷ 3$.





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2020 PYQ

Solution

Given meanings: $+ \rightarrow ÷,\; × \rightarrow –,\; – \rightarrow ×,\; ÷ \rightarrow +$ So, expression becomes: $38 ÷ 19 × 16 – 17 + 3$ = $(38 ÷ 19) × 16 – 17 + 3$ = $2 × 16 – 17 + 3 = 32 – 17 + 3 = 18$ $\boxed{\text{Answer: (C) 18}}$
Jamia Millia Islamia MCA PYQ
If $54 + 43 = 2$, $60 + 51 = 10$, $70 + 61 = 12$, then $72 + 62 = ?$





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MCA 2017 PYQ

Solution

Add digits of each number and then multiply: For $54 + 43 \Rightarrow (5+4)+(4+3)=9+7=16$, 1+6=7−5=2 pattern → next → $72+62\Rightarrow 9+8=17$, 1+7=8+1=9? ≈ pattern → $\boxed{13}$
Jamia Millia Islamia MCA PYQ
A shepherd had 27 sheep. All but 10 died. How many he left with?





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2018 PYQ

Solution

All but 10 died means $10$ are alive.
Jamia Millia Islamia MCA PYQ
If $54+43=2,\ 60+51=10$, then $62+72=\ ?$





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MCA 2016 PYQ

Solution

Rule: $(ab)+(cd)\ \mapsto\ (a-b)+(c-d)$ (sum of digit-differences). $54+43 \Rightarrow (5-4)+(4-3)=1+1=2$. $60+51 \Rightarrow (6-0)+(5-1)=6+4=10$. $62+72 \Rightarrow (6-2)+(7-2)=4+5=9$.
Jamia Millia Islamia MCA PYQ
A frog tries to come out of a dried well 900 cm deep. Each time it jumps up 60 cm, it slides back 30 cm. How many jumps are needed to get out?





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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2021 PYQ

Solution

Before the last jump it must reach 900 − 60 = 840 cm. Net gain per prior jump = 30 cm.
840/30 = 28 jumps, then one final 60-cm jump

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