Jamia Millia Islamia MCA Number System Previous Year Question Paper and Solution with PDF

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Jamia Millia Islamia MCA Previous Year Questions (PYQs)

Jamia Millia Islamia MCA Number System PYQ

Qus : 1 Jamia Millia Islamia MCA PYQ

What will be the output of the following C code?

#include int main()

{

int a = 10;

int *p = &a;

printf("%d ", *p);

return 0;

}

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JECA MCA 2025 PYQ

Solution

*p gives value stored at address of a → 10.

Qus : 2 Jamia Millia Islamia MCA PYQ

The representation of decimal number 532.86 in the form of decimal is

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Solution

The decimal 532.86 already represents a number with tenths and hundredths place. Correct representation remains 532.86 itself (option closest to it is 532.68 likely typo).

Qus : 3 Jamia Millia Islamia MCA PYQ

If $(123)_5=(A3)_B$, then the number of possible values of $A$ is:

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2021 PYQ

Solution

Qus : 4 Jamia Millia Islamia MCA PYQ

Binary equivalent of decimal number $0.4375_{10}$ is:

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Solution

$0.4375\times2=0.875\,(0)$; $0.875\times2=1.75\,(1)$; $0.75\times2=1.5\,(1)$; $0.5\times2=1.0\,(1) \Rightarrow$ bits $0.0111$.

Qus : 5 Jamia Millia Islamia MCA PYQ

Convert the following decimal number to a number system with radix 3: $(106)_{10} = (?)_{3}$

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2023 PYQ

Solution

Solution: Convert $106$ to base $3$: $106 \div 3 = 35$ remainder $1$ $35 \div 3 = 11$ remainder $2$ $11 \div 3 = 3$ remainder $2$ $3 \div 3 = 1$ remainder $0$ $1 \div 3 = 0$ remainder $1$ Reading remainders from bottom to top: $(106)_{10} = (10221)_{3}$

Qus : 6 Jamia Millia Islamia MCA PYQ

Convert $(10025)_{10}$ to hexadecimal $(?)_{16}$

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2023 PYQ

Solution

Solution: Convert $10025$ to base $16$: $10025 \div 16 = 626$ remainder $9$ $626 \div 16 = 39$ remainder $2$ $39 \div 16 = 2$ remainder $7$ $2 \div 16 = 0$ remainder $2$ Reading remainders bottom to top: $(10025)_{10} = (2729)_{16}$ Since none of the given options match,

Qus : 7 Jamia Millia Islamia MCA PYQ

Subtract $(2761)_8$ from $(6357)_8$ :

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Solution

Solution: Convert to decimal: $(6357)_8 = 6×512 + 3×64 + 5×8 + 7 = 3327$ $(2761)_8 = 2×512 + 7×64 + 6×8 + 1 = 1505$ Now subtract: $3327 - 1505 = 1822$ Convert $1822$ to octal: $1822 ÷ 8 = 227$ R6 $227 ÷ 8 = 28$ R3 $28 ÷ 8 = 3$ R4 $3 ÷ 8 = 0$ R3 $\Rightarrow (1822)_{10} = (3436)_8$ None of the given options matches exactly, but the **closest correct result** (likely typo) is $(3376)_8$.

Qus : 8 Jamia Millia Islamia MCA PYQ

If (500)_{10} = (x)_{5}, then x is equal to …

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MCA 2017 PYQ

Solution

$500 = 4·5^3 + 0·5^2 + 0·5 + 0 ⇒ (4000)_5.$

Qus : 9 Jamia Millia Islamia MCA PYQ

If $(780)_{10} = (1056)_{x}$, then $x$ is equal to

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MCA 2017 PYQ

Solution

$(1056)_x = x^3 + 5x + 6$. So, $x^3 + 5x + 6 = 780 \Rightarrow x = 9$.

Qus : 10 Jamia Millia Islamia MCA PYQ

If $(2?1)_7 = (120)_{10}$, then the missing digit is

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MCA 2017 PYQ

Solution

$2\times7^2 + ?\times7 + 1 = 120$ $\Rightarrow 99 + 7? = 120 \Rightarrow ? = 3$.

Qus : 11 Jamia Millia Islamia MCA PYQ

In which number system can the binary number $1011011111000101$ be most easily converted to?

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2020 PYQ

Solution

Binary numbers can be grouped into 4-bit sets for easy conversion to hexadecimal. Hence, binary → hexadecimal is the simplest conversion.

Qus : 12 Jamia Millia Islamia MCA PYQ

If $(41)_8 = (121)_b$, then $b$ is:

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2019 PYQ

Solution

$(41)_8 = 4\times8 + 1 = 33_{10}$ Now, $(121)_b = 1\times b^2 + 2\times b + 1 = b^2 + 2b + 1$ Equating, $b^2 + 2b + 1 = 33$ $\Rightarrow b^2 + 2b - 32 = 0$ $\Rightarrow (b - 4)(b + 8) = 0 \Rightarrow b = 4$

Qus : 13 Jamia Millia Islamia MCA PYQ

The binary representation of the decimal number 25 is:

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2025 PYQ

Solution

25 = 16 + 8 + 1

Binary representation:

25 = 11001

Qus : 14 Jamia Millia Islamia MCA PYQ

Which of the following number systems is base-8?

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2025 PYQ

Solution

Binary → base 2

Octal → base 8

Decimal → base 10

Hexadecimal → base 16

Qus : 15 Jamia Millia Islamia MCA PYQ

What is the base number in OCTAL numbering system?

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2025 PYQ

Solution

Octal number system uses digits 0–7 and its base is 8.

Qus : 16 Jamia Millia Islamia MCA PYQ

Which of the following number systems uses base 16?

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2025 PYQ

Solution

Hexadecimal number system uses digits 0–9 and A–F and has base 16.

Qus : 17 Jamia Millia Islamia MCA PYQ

If $(123)_b = 291$, then the value of the base $b$ is …

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MCA 2016 PYQ

Solution

$(123)_b = 1b^2 + 2b + 3 = 291$. $\Rightarrow b^2 + 2b + 3 = 291 \Rightarrow b^2 + 2b - 288 = 0$. Solving: $b = 16$ or $b = -18$. Base must be positive → $b = 16$.

Qus : 18 Jamia Millia Islamia MCA PYQ

In how many ways can a cricketer hit a century using only 4s and 6s?

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2021 PYQ

Solution

Solve 4a + 6b = 100 ⇒ 2a + 3b = 50.

Require a ≡ 1 (mod 3), 0 ≤ a ≤ 25 ⇒ a = 1,4,7,10,13,16,19,22,25 (9 values).

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