Jamia Millia Islamia MCA Seating Arrangement Previous Year Question Paper and Solution with PDF

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Jamia Millia Islamia MCA
Previous Year Questions

Jamia Millia Islamia MCA
Previous Year Questions
Jamia Millia Islamia MCA

Jamia Millia Islamia MCA Previous Year Questions (PYQs)

Jamia Millia Islamia MCA Seating Arrangement PYQ

Qus : 1 Jamia Millia Islamia MCA PYQ

P, Q, R, S, T, U, V and W are sitting round a circle facing the centre:

• P is second to the right of T who is neighbour of R and V.

• S is not neighbour of P.

• V is neighbour of U.

• Q is not between S and W; W is not between U and S.

Who is sitting opposite to U?

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MILLIA ISLAMIA MCA 2018 PYQ

Solution

Place T, so P is two to T’s right. Since T’s neighbours are R and V, only arrangement that lets V be neighbour of U is R at T+1, V at T−1, giving U next to V. Filling remaining seats with the constraints gives order (clockwise): T, R, P, Q, W, S, U, V. Opposite to U (four away) is P.

Qus : 2 Jamia Millia Islamia MCA PYQ

Q, R, S, T, U and V are seated in a straight line facing North. S is second to the right of T and T is second to the right of Q. R is to the left of Q and second to the left of V. What is Q’s position with respect to S?

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Jamia Millia Islamia MCA Previous Year PYQ Jamia Millia Islamia MCA JAMIA MCA 2016 PYQ

Solution

Let positions be 1 (leftmost) to 6 (rightmost). $T$ is second right of $Q$ ⇒ $T=Q+2$. $S$ is second right of $T$ ⇒ $S=T+2=Q+4$. So $Q$ can be 1 or 2. Try $Q=2$ ⇒ $T=4$, $S=6$. $R$ is left of $Q$ and 2 left of $V$ ⇒ take $R=1$, then $V=3$ (fits). Arrangement: $1\!:\!R,\ 2\!:\!Q,\ 3\!:\!V,\ 4\!:\!T,\ 5\!:\!U,\ 6\!:\!S$. Thus $Q$ is **fourth to the left** of $S$.