Delhi University MCA Complex Numbers Previous Year Question Paper and Solution with PDF

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Delhi University MCA Previous Year Questions (PYQs)

Delhi University MCA Complex Numbers PYQ

Qus : 1 Delhi University MCA PYQ

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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2019 PYQ

Solution

Qus : 2 Delhi University MCA PYQ

Let $z=\cos\!\left(\frac{2\pi}{7}\right)+i\sin\!\left(\frac{2\pi}{7}\right)$. Then the principal argument of $\overline{(1-z^{2}})$ is equal to

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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2019 PYQ

Solution

Qus : 3 Delhi University MCA PYQ

The complex number

is the root of the quadratic equation with real coefficients

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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2019 PYQ

Solution

Qus : 4 Delhi University MCA PYQ

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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2021 PYQ

Solution

Qus : 5 Delhi University MCA PYQ

Let $Re(z)$ and $Im(z)$ be the real and imaginary parts of any complex number $z$, and $\arg(z)$ denotes the principal argument of $z$. Let $z_1$ and $z_2$ be two distinct complex numbers such that $\operatorname{Re}(z_1) = |z_1 - 2| \quad \text{and} \quad \operatorname{Re}(z_2) = |z_2 - 2|.$ If $\arg(z_1 - z_2) = \frac{\pi}{6},$ then

(a) $\operatorname{Im}(z_1 + z_2) = 4\sqrt{3}$

(b) $\operatorname{Im}(z_1 + z_2) = \dfrac{4}{\sqrt{3}}$

(d) $\operatorname{Re}(z_1 - z_2) = 9$

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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2021 PYQ