Let Part A = \(a\) questions (1 mark), Part C = \(c\) questions (3 marks).
So, \(a + 23 + c = 100 \Rightarrow a + c = 77\).
Total marks = \(a + 46 + 3c\).
Part A marks ≥ 60% total marks:
\(\Rightarrow a \geq 0.6(a + 46 + 3c)\)
\(\Rightarrow a \geq 0.6a + 27.6 + 1.8c\)
\(\Rightarrow 0.4a \geq 27.6 + 1.8c\)
\(\Rightarrow a \geq 69 + 4.5c\).
Using \(a = 77 - c\):
\(77 - c \geq 69 + 4.5c \Rightarrow 8 \geq 5.5c \Rightarrow c \leq 1.45\).
So, \(c = 1\).
Answer: Part C has 1 question.
Online Test Series, Information About Examination,
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and More.