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If $y=\sin ^{-1}(\frac{{x}^2+1}{\sqrt[]{1+3{x}^2+{x}^4}}),\, (x>0),$ then $\frac{dy}{dx}$=

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Mahendra , NIMCET ASPIRANT
Commented Mar 04 , 2024

Simply use the arcsin formula for differentiation

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