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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If F|= 40N (Newtons), |D| = 3m, and $\theta={60^{\circ}}$, then the work done by F acting
from P to Q is
Solution
Formula for work done:
\[ W = |F| \cdot |D| \cdot \cos\theta \]
Given:
- \( |F| = 40 \, \text{N} \)
- \( |D| = 3 \, \text{m} \)
- \( \theta = 60^\circ \)
Step 1: Plug in the values:
\[ W = 40 \cdot 3 \cdot \cos(60^\circ) \]
Step 2: Use \( \cos(60^\circ) = \frac{1}{2} \)
\[ W = 40 \cdot 3 \cdot \frac{1}{2} = 60 \, \text{J} \]
✅ Final Answer: $\boxed{60 \, \text{J}}$
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