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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If three distinct numbers are chosen randomly from the first 100 natural numbers, then
the probability that all three of them are divisible by both 2 and 3 is
Solution
✔️ Verified Probability
Total numbers divisible by 6 from 1 to 100: 16
\[ \binom{100}{3} = 161700, \quad \binom{16}{3} = 560 \]
Probability: \[ \frac{560}{161700} = \frac{4}{1155} \]
✅ Final Answer: \(\boxed{\frac{4}{1155}}\)
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