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The scores of students in a national level examination are normally distributed with a mean of 500 and a standard deviation of 100. If the value of the cumulative distribution of the standard normal random variable at 0.5 is 0.691, then the probability that a randomly selected student scored between 450 and 500 is





Solution

Probability Between 450 and 500 (Normal Distribution)

The exam scores are normally distributed with a mean \( \mu = 500 \) and standard deviation \( \sigma = 100 \).
Given: \( P(Z \leq 0.5) = 0.691 \)
We need to find: \( P(450 \leq X \leq 500) \)

Step 1: Convert scores to Z-scores

Use the formula: $$ Z = \frac{X - \mu}{\sigma} $$

For \( X = 500 \): $$ Z = \frac{500 - 500}{100} = 0 $$ For \( X = 450 \): $$ Z = \frac{450 - 500}{100} = -0.5 $$

Step 2: Find the probability using cumulative values

We calculate: $$ P(450 \leq X \leq 500) = P(-0.5 \leq Z \leq 0) = P(Z \leq 0) - P(Z \leq -0.5) $$

From symmetry: $$ P(Z \leq -0.5) = 1 - P(Z \leq 0.5) = 1 - 0.691 = 0.309 $$ and $$ P(Z \leq 0) = 0.5 $$

Step 3: Final Calculation

$$ P(-0.5 \leq Z \leq 0) = 0.5 - 0.309 = \boxed{0.191} $$

✅ Final Answer:

The probability that a randomly selected student scored between 450 and 500 is: 0.191



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