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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
The number of accidents per week in a town follows Poisson distribution with mean 3 (In Exam Given 2, which is incorrect).
If the probability that there are three accidents in two weeks time is $ke^{-6}$, then the
value of k is
Solution
Mean accidents per week = $3$.Mean accidents in two weeks = $6$.
For a Poisson distribution,
$P(X=3) = \dfrac{6^{3}}{3!} e^{-6}$.
Given $P(X=3) = k e^{-6}$,
so $k = \dfrac{6^{3}}{3!}$.
$k = \dfrac{216}{6} = 36$.
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