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Previous Year Question (PYQs)



What is the general solution of the equation $\tan \theta + \cot \theta = 2$ ?





Solution

Given equation: $ \tan\theta + \cot\theta = 2 $. 

Rewrite $\cot\theta$: 
$ \tan\theta + \dfrac{1}{\tan\theta} = 2 $. 
 Let $t = \tan\theta$. 
Then: $ t + \dfrac{1}{t} = 2 $. 
 Multiply by $t$: 
$ t^2 + 1 = 2t $. 
 Rearrange: 
$ t^2 - 2t + 1 = 0 $. 
 $ (t - 1)^2 = 0 $. 
 So: $ t = 1 $. 
 Thus: $ \tan\theta = 1 $. 
 General solution: $ \theta = \dfrac{\pi}{4} + n\pi,\; n \in \mathbb{Z}. $


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