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Previous Year Question (PYQs)
4
A person walks 8 km north, turns right, walks 4 km, turns right again and walks 6 km.
Finally, he turns left and walks 3 km. How far is he from the starting point?
Solution
A person walks $8$ km north.
Position: $(0,\,8)$
He turns right (east) and walks $4$ km.
Position: $(4,\,8)$
He turns right again (south) and walks $6$ km.
Position: $(4,\,2)$
He turns left (east) and walks $3$ km.
Final position: $(7,\,2)$
Distance from starting point:
$ d = \sqrt{(7-0)^2 + (2-0)^2} $
$ d = \sqrt{49 + 4} $
$ d = \sqrt{53} $
$d=7.28$
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