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To provide a memory capacity of 32K X 16 how many address lines and data lines are required? 

1. address lines=14, data lines=16 
2. address lines=15, data lines=16 
3. address lines=14, data lines=4 
4. address lines=15, data lines=4





Solution

Given: Memory capacity = 32K × 16

Step 1: 32K means 32 × 1024 = 32768 memory locations.
To address 32768 locations, we need: $$\log_2(32768) = 15 \; \text{address lines}$$

Step 2: Each location stores 16 bits = 16 data lines.


Address lines required: 15

Data lines required: 16

Answer: Option 2



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