Given: Memory capacity = 32K × 16
Step 1: 32K means 32 × 1024 = 32768 memory locations.
To address 32768 locations, we need:
$$\log_2(32768) = 15 \; \text{address lines}$$
Step 2: Each location stores 16 bits = 16 data lines.
Address lines required: 15
Data lines required: 16
Answer: Option 2
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