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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If $\cos\alpha + \cos\beta + \cos\gamma = 3\pi$, then
$\alpha((\beta + \gamma) + \beta(\gamma + \alpha) + \gamma(\alpha + \beta))$ equals
Solution
Expression: $\alpha((\beta+\gamma)) + \beta((\gamma+\alpha)) + \gamma((\alpha+\beta))$ $= 2(\alpha\beta + \beta\gamma + \gamma\alpha)$ But no relation with $\pi$ is relevant; data implies constants. Numerically simplifying: $\boxed{6}$ $\boxed{\text{Answer: (C) 6}}$Online Test Series, Information About Examination,
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