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Previous Year Question (PYQs)



Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is...





Solution

Each person can choose any of 3 houses ⇒ total cases $= 3^3 = 27.$ All three apply for the same house ⇒ favorable cases $= 3.$ So $P = \dfrac{3}{27} = \dfrac{1}{9}.$


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