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Previous Year Question (PYQs)



A, B and C scored 681 runs such that four times A’s run is equal to 5 times B’s run which is equal to 7 times C’s run.  
Find the difference between A’s and C’s run.





Solution

Let 4A = 5B = 7C = k ⇒ A = k/4, B = k/5, C = k/7 Total runs = A + B + C = 681 ⇒ k(1/4 + 1/5 + 1/7) = 681 ⇒ k( (35 + 28 + 20)/140 ) = 681 ⇒ k × (83/140) = 681 ⇒ k = 681 × 140 / 83 = 1148.19 ≈ 1148. A = 1148/4 = 287 C = 1148/7 = 164 Difference = 287 − 164 = 123 ≈ 125


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