Solution

Consider ar as a 3-dimensional array declared as:

data_type ar[a][b][c];

Here, the array element ar[m][n][o] can be represented in pointer form as:

*(*(*(ar + m) + n) + o)

Step-by-step understanding:

• ar is a pointer to the first 2D array ar[0].
• ar + m moves the pointer to the m^th 2D array → ar[m].
• *(ar + m) gives the address of the first 1D array inside ar[m].
• *(ar + m) + n moves to the n^th 1D array → ar[m][n].
• *(*(ar + m) + n) gives the address of the first element of that 1D array.
• *(*(*(ar + m) + n) + o) finally gives the element ar[m][n][o].

✅ Final Answer: *(*(*(ar + m) + n) + o)