Let the values of $p$, for which the shortest distance between the lines $\dfrac{x+1}{3}=\dfrac{y}{4}=\dfrac{z}{5}$ and $\vec r=(p\hat i+2\hat j+\hat k)+\lambda(2\hat i+3\hat j+4\hat k)$ is $\dfrac{1}{\sqrt6}$, be $a,b$ $(a
1$\dfrac{3}{2}$
29
318
4$\dfrac{2}{3}$

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Solution