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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If the ratio of sum of $m$ terms and $n$ terms of an A.P. be $m^2:n^2$, then the ratio of its $m$th and $n$th terms will be
Solution
$S_m/S_n = m^2/n^2$ We know $S_n = \dfrac{n}{2}[2a+(n-1)d]$ $\Rightarrow \dfrac{m[2a+(m-1)d]}{n[2a+(n-1)d]} = \dfrac{m^2}{n^2}$ Simplify → $\dfrac{2a+(m-1)d}{2a+(n-1)d} = \dfrac{m}{n}$ $\Rightarrow \text{ratio of } t_m : t_n = (2m-1):(2n-1)$Online Test Series, Information About Examination,
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