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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If
$
f(x)=
\begin{cases}
x \sin\left(\frac{1}{x}\right), & x \ne 0 \\
0, & x = 0
\end{cases}
$
then
Solution
Solution: lim_{x→0} x·sin(1/x) = 0 ⇒ f is continuous at 0. f'(0) = lim_{x→0} [x sin(1/x)]/x = sin(1/x) But sin(1/x) has no limit as x→0⁺ or x→0⁻. ⇒ Both f'(0+) and f'(0-) do not exist.Online Test Series, Information About Examination,
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Online Test Series, Information About Examination,
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and More.
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