If $a,b$ are the roots of $x^2+px+1=0$ and $c,d$ are the roots of $x^2+qx+1=0$,…

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If $a,b$ are the roots of $x^2+px+1=0$ and $c,d$ are the roots of $x^2+qx+1=0$, the value of $E=(a-c)(b-c)(a+d)(b+d)$ is

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Using symmetric sums and simplification, $E=q^2-p^2$ Answer: $\boxed{q^2-p^2}$

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