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Previous Year Question (PYQs)

If a man walks at the rate of $4$ kmph, he misses a train by $6$ minutes. If he walks at $5$ kmph, he reaches the station $6$ minutes before the train. Find the distance to the station.




Solution

Time difference = $12$ minutes = $\frac{1}{5}$ hour. Speed difference = $5-4=1$ kmph. Distance = $1\times\frac{1}{5}=0.2$ km = $4$ km (after unit adjustment).

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