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Previous Year Question (PYQs)
3
If $A_1,A_2$ be two A.M.’s and $G_1,G_2$ be two G.M.’s between $a$ and $b$, then
$\dfrac{A_1+A_2}{G_1G_2}$ is equal to
Solution
For A.M.’s between $a$ and $b$:
$A_1=\dfrac{2a+b}{3},\quad A_2=\dfrac{a+2b}{3}$
So,
$A_1+A_2=\dfrac{2a+b+a+2b}{3}=a+b$
For G.M.’s between $a$ and $b$:
$G_1=\sqrt[3]{a^2b},\quad G_2=\sqrt[3]{ab^2}$
So,
$G_1G_2=\sqrt[3]{a^3b^3}=ab$
Hence,
$\dfrac{A_1+A_2}{G_1G_2}=\dfrac{a+b}{ab}$
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