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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If the curve $ay+x^2=7$ and $x^3=y$ cut orthogonally at $(1,1)$, then the value of $a$ is
Solution
From $ay+x^2=7$: $a\dfrac{dy}{dx}+2x=0$ $\Rightarrow \dfrac{dy}{dx}=-\dfrac{2x}{a}$ From $y=x^3$: $\dfrac{dy}{dx}=3x^2$ At $(1,1)$: $m_1=-\dfrac{2}{a},\quad m_2=3$ For orthogonal curves: $m_1m_2=-1$ $-\dfrac{2}{a}\times3=-1$ $\Rightarrow a=6$Online Test Series, Information About Examination,
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