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Previous Year Question (PYQs)
1
At the time of marriage a man was 6 years older than his wife but 12 years after the marriage he was $\frac{6}{5}$ times the age of his wife. What were their ages in years at the time of marriage?
Solution
Let wife’s age at marriage = $x$
Man’s age = $x + 6$
After 12 years:
$\frac{x + 18}{x + 12} = \frac{6}{5}$
$5x + 90 = 6x + 72$
$x = 18$
Man’s age = $24$
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