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Previous Year Question (PYQs)



At the time of marriage a man was 6 years older than his wife but 12 years after the marriage he was $\frac{6}{5}$ times the age of his wife. What were their ages in years at the time of marriage?





Solution

Let wife’s age at marriage = $x$ Man’s age = $x + 6$ After 12 years: $\frac{x + 18}{x + 12} = \frac{6}{5}$ $5x + 90 = 6x + 72$ $x = 18$ Man’s age = $24$


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