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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
The probability mass function of Random variable $X$ is:
$P(X=x)=(0.6)^x(0.4)^{1-x}, ; x=0,1$
The variance of $X$ is:
Solution
For $x=0$:
$P(0)=(0.6)^0(0.4)^1=0.4$
For $x=1$:
$P(1)=(0.6)^1(0.4)^0=0.6$
So $X$ follows Bernoulli distribution with
$p=0.6$
Variance of Bernoulli:
$\mathrm{Var}(X)=p(1-p)$
$=0.6(0.4)$
$=0.24$
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