$\text{Value after } n \text{ years}=P(1-r)^n$
Here,
$P=20000$
$r=0.1$
$n=10$
Value
$=20000(0.9)^{10}$
Given
$(0.9)^{10}=0.35$
So,
$=20000\times 0.35$
$=7000$
Online Test Series, Information About Examination,
Syllabus, Notification
and More.
Online Test Series, Information About Examination,
Syllabus, Notification
and More.