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Previous Year Question (PYQs)



The cost of a machine is Rs. $20,000$ and its estimated useful life is $10$ years. The scrap value of the machine, when its value depreciates at $10%$ p.a., is (use $(0.9)^{10}=0.35$)





Solution

$\text{Value after } n \text{ years}=P(1-r)^n$


Here,


$P=20000$


$r=0.1$


$n=10$


Value


$=20000(0.9)^{10}$


Given


$(0.9)^{10}=0.35$


So,


$=20000\times 0.35$


$=7000$



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