A coin is tossed successively three times. Find the Probability $(P)$, Event $(E)$, Sample space $(S)$ of getting exactly one head or two heads, where $n$ is number of occurrence.
(A) $n(S)=8$ and $n(E)=4$
(B) $n(E)=6$ and $n(S)=8$
(C) $P(E)=\frac{3}{4}$
(D) $P(E)=\frac{1}{2}$
Choose the correct answer from the options given below :
Sample space for 3 tosses:
$S={HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}$
Thus
$n(S)=8$
Event: exactly 1 head or 2 heads
1 head → ${HTT,THT,TTH}$
2 heads → ${HHT,HTH,THH}$
So
$n(E)=6$
Probability
$P(E)=\frac{6}{8}=\frac{3}{4}$
Thus correct statements:
(B) and (C)
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