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Previous Year Question (PYQs)



Let PQ and MN be two straight lines touching the circle $x^2 + y^2 - 4x - 6y - 3 = 0$ at the points $A$ and $B$ respectively. Let $O$ be the centre of the circle and $\angle AOB = \pi/3$. Then the locus of the point of intersection of the lines PQ and MN is:





Solution

Given circle

$x^2 + y^2 - 4x - 6y - 3 = 0$

$C(2,3)$ & $r = 4$

$\cos 30^\circ = \frac{r}{OR} = \frac{4}{OR}$

$\Rightarrow OR = \frac{8}{\sqrt{3}}$

Now

$OR^2 = (h - 2)^2 + (k - 3)^2$

$\Rightarrow 3(x^2 + y^2) - 12x - 18y - 25 = 0$



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