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Previous Year Question (PYQs)



The system of equations

$3x + y + 4z = 3$
$2x + ay - z = -3$
$x + 2y + z = 4$

has no solution, then the value of $\alpha$ is equal to:





Solution

for no solution $\Delta = 0$

$\begin{vmatrix} 3 & 1 & 4 \ 2 & \alpha & -1 \ 1 & 2 & 1 \end{vmatrix} = 0$

$\Rightarrow 3(\alpha + 2) + 1(-1 - 2) + 4(4 - \alpha) = 0$

$\Rightarrow 3\alpha + 6 - 3 + 16 - 4\alpha = 0$

$\Rightarrow 19 - \alpha = 0 \Rightarrow \alpha = 19$

$\Delta_x = \begin{vmatrix} 3 & 1 & 4 \ -3 & \alpha & -1 \ 4 & 2 & 1 \end{vmatrix}$

$\neq 0$

$\therefore$ no solution for $\alpha = 19$


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