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Previous Year Question (PYQs)



Let $L$ be the line $\dfrac{x+1}{2}=\dfrac{y+1}{3}=\dfrac{z+3}{6}$ and let $S$ be the set of all points $(a,b,c)$ on $L$, whose distance from the line $\dfrac{x+1}{2}=\dfrac{y+1}{3}=\dfrac{z-9}{0}$ along the line $L$ is $7$. Then $\sum_{(a,b,c)\in S}(a+b+c)$ is equal to:





Solution

Parametrize line $L$: $x=-1+2t,y=-1+3t,z=-3+6t$. Distance condition gives two values of $t$. Sum $(a+b+c)$ for both points gives $28$


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