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Previous Year Question (PYQs)
4
Let $A(1,0),; B(2,-1)$ and $C\left(\frac{7}{3},\frac{4}{3}\right)$ be three points.
If equation of bisector of angle $ABC$ is $\alpha x+\beta y=5$, then $\alpha^2+\beta^2$ is:
Solution
Using internal angle bisector
Slope $=-3$
Equation ⇒ $\alpha=3,; \beta=1$
$\alpha^2+\beta^2=10$
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