$ f(x) = \begin{cases} \cos \pi x, & x \to 1^- \ -\frac{\sin(x-1)}{(x-1)}, & x \to 1^+ \end{cases} $
RHL $ = \lim_{x \to 1} -\frac{\sin(x-1)}{(x-1)} = -1 $
LHL $ = \lim_{x \to 1} \cos \pi x = -1,; f(1) = -1 $
$ f(x) $ is continuous at $ x = 1 $
$ f(x) = \begin{cases} -\frac{\sin(x-1)}{(x-1)}, & x \to -1^- \ \cos \pi x, & x \to -1^+ \end{cases} $
RHL $ = \lim_{x \to -1} \cos \pi x = -1 $
LHL $ = \lim_{x \to -1} -\frac{\sin(x-1)}{(x-1)} = \frac{\sin 2}{2} $
$ f(x) $ is discontinuous at $ x = -1 $
Online Test Series, Information About Examination,
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Online Test Series, Information About Examination,
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and More.