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Previous Year Question (PYQs)



An ellipse has center at $ (1,-2) $, one focus at $ (3,-2) $ and one vertex at $ (5,-2) $. Then the length of its latus rectum is :





Solution


$ CA_1 = a = 4 $

$ CF = ae = 2 $

$ \Rightarrow e = \frac{1}{2} $

$ LR = 2\left( \frac{a}{e} - ae \right) $

$ = 2 \times \frac{1}{2} \left( \frac{4}{1/2} - 2 \right) $

$ = 6 $



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