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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If $A$ and $B$ are two events associated to some experiment $E$ such that $P(A)=0.5,\ P(B)=0.4,\ P(A\cap B)=0.3$, then $P\left(\frac{A^c}{B^c}\right)$ is equal to
Solution
$ P(A\cup B)=P(A)+P(B)-P(A\cap B) $ $ =0.5+0.4-0.3=0.6 $ $ P((A\cup B)^c)=1-0.6=0.4 $ $ P(B^c)=1-0.4=0.6 $ $ P(A^c|B^c)=\frac{P(A^c\cap B^c)}{P(B^c)}=\frac{0.4}{0.6}=\frac{2}{3} $Online Test Series, Information About Examination,
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