Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET

Previous Year Question (PYQs)

Out of $(2n+1)$ consecutively numbered tickets, three tickets are drawn at random. The probability that the numbers on them are in arithmetic progression is




Solution

Total ways: $\binom{2n+1}{3}$ AP triples: choose middle term and common difference Total AP = $n(2n+1)$ Probability = $\frac{n(2n+1)}{\binom{2n+1}{3}} = \frac{3n}{4n^2 -1}$ Final Answer: $\boxed{\frac{3n}{4n^2 -1}}$

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More
Ask Your Question or Put Your Review.

loading...