Aspire's Library
A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
In a multi user operating system, 20 requests are made to use a particular resource per hour, on an average. The probability that no request is made in 45 minutes is
Solution
Average requests per hour = $20$
Time = $45$ minutes $= \frac{3}{4}$ hour
Mean number of requests in $45$ minutes:
$\lambda = 20 \times \frac{3}{4} = 15$
Using Poisson distribution:
$P(X=0)=e^{-\lambda}\frac{\lambda^0}{0!}$
$P(X=0)=e^{-15}$
Online Test Series, Information About Examination,
Syllabus, Notification
and More.
View More
Online Test Series, Information About Examination,
Syllabus, Notification
and More.
View More
Ask Your Question or Put Your Review.
