Solution

Given expression is:

$(A+B*D)/(E-F)+G$

First solve according to operator precedence:

$B*D$

So, expression becomes:

$(A+(B*D))/(E-F)+G$

Prefix of $B*D$ is:

$*BD$

Prefix of $A+B*D$ is:

$+A*BD$

Prefix of $E-F$ is:

$-EF$

Now prefix of $\frac{A+B*D}{E-F}$ is:

$/+A*BD-EF$

Finally add $G$:

$+/+A*BD-EFG$

So, statement $1$ is true.

Prefix is not simply the reverse of postfix.

So, statement $2$ is false.

The order of operands in infix and postfix remains:

$A,B,D,E,F,G$

So, statement $3$ is true.

The order of operands in infix, prefix, and postfix also remains the same:

$A,B,D,E,F,G$

So, statement $4$ is true.

Correct statements are:

$1,3,$ and $4$