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Previous Year Question (PYQs)



If $x,y$ are real numbers such that $2^{x+\frac{1}{2}}\times 4^{y-\frac{5}{6}}=3^{x-\frac{1}{2}}\times 9^{y-\frac{1}{3}}$ then which of the following is true?





Solution

$2^{x+\frac{1}{2}}\times 4^{y-\frac{5}{6}}=3^{x-\frac{1}{2}}\times 9^{y-\frac{1}{3}}$ 
Convert powers: $4=2^2,\quad 9=3^2$ 

$2^{x+\frac{1}{2}}\times 2^{2y-\frac{5}{3}}=3^{x-\frac{1}{2}}\times 3^{2y-\frac{2}{3}}$ 
$2^{x+2y-\frac{7}{6}}=3^{x+2y-\frac{7}{6}}$ 

Since bases are different, 
$x+2y-\frac{7}{6}=0$ 
$6x+12y-7=0$


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